In: Chemistry
electronegativity decreases down in a group : Ba < Ca , ,, P
<N same group members
electronegativity increases from left to right in a period Si <
P ,,,, N < F
Since Ba is below Ca in 2nd group , Ba has least value
Si and P are in same period So Si has less value than P
All can be solved using periodic table
Hence answer : Ranking elements in the increasing order of
electro negativity
as
Ba < Ca < Si < P < N < F
Ba :1
Ca :2
Si :3
P;4
N:5
F;6
METAL AND NON METAL BONDS ARE IONIC .Hence they will be
purely
ionic.
let us find out electronegativity difference between atoms
in covalent bond . When the difference is small, the compound
will be covalent
A) H-C
DIFFERENCE in electronegativity
dE.N = 2.56 -2.26 = 0.3
B) C-O
dE.N = 3.44-2.55 = 0.89 : polar
C) Be-Cl
dE.N = 3.16 -1.57 = 1.59 ;polar
D) C-S
dE.N = 2.58 -2.56 = 0.02 ; nonpolar
E) F-Cl
dEN = 3.96 - 3.16 = 0.8 : polar
F) H-N
dEN = 3.04 -2.20 =0.84 : polar
G) K-Cl = ionic
H) Si-P =
dEN = 2.19-1.90 = 0.29
I) Mn-O= ionic bond
J) B-N =
dEN = 3.04 - 2.04 =1 : polar
dE.N value smaller than 0.5 considered as covalent
hence answer is
A)C-H and
D) C-S
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Thank you