Question

Describe the sampling distribution of ModifyingAbove p with caret. Assume the size of the population is 25 comma 000. nequals900​, pequals0.235 Describe the shape of the sampling distribution of ModifyingAbove p with caret. Choose the correct answer below. A. The shape of the sampling distribution of ModifyingAbove p with caret is not normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis greater than or equals 10. B. The shape of the sampling distribution of ModifyingAbove p with caret is approximately normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis greater than or equals 10. C. The shape of the sampling distribution of ModifyingAbove p with caret is approximately normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis less than 10. D. The shape of the sampling distribution of ModifyingAbove p with caret is not normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis less than 10. Determine the mean of the sampling distribution of ModifyingAbove p with caret. mu Subscript ModifyingAbove p with caret Baseline equals 0.235 0.235 ​(Round to three decimal places as​ needed.) Determine the standard deviation of the sampling distribution of ModifyingAbove p with caret. sigma Subscript ModifyingAbove p with caret Baseline equals nothing ​(Round to three decimal places as​ needed.)

Answer 1

Describe the sampling distribution of ModifyingAbove p with caret. Assume the size of the population is 25 000. nequals900​, pequals0.235 Describe the shape of the sampling distribution of ModifyingAbove p with caret. Choose the correct answer below.

N=25000, n=900, p=0.235

To check, n    <    0.05*N we have 900 < 0.05*25000

np=211.5 and n(1-p)=688.5

both np and n(1-p) are greater than 10.

The correct option is

B. The shape of the sampling distribution of ModifyingAbove p with caret is approximately normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis greater than or equals 10.

Determine the mean of the sampling distribution of ModifyingAbove p with caret. mu Subscript ModifyingAbove p with caret Baseline equals 0.235 ​(Round to three decimal places as​ needed.)

Determine the standard deviation of the sampling distribution of ModifyingAbove p with caret. sigma Subscript ModifyingAbove p with caret Baseline equals 0.014 ​(Round to three decimal places as​ needed.)

se = sqrt(p*(1-p)/n) = sqrt(0.235*(1-0.235)/900) =0.014133