Find dy/dx for a & b
a) sin x+cos y=1
b) cos x^2 = xe^y
c)Let f(x) = 5 /2 x^2 − e^x . Find the value of x for which the
second derivative f'' (x) equals zero.
d) For what value of the constant c is the function f continuous
on (−∞,∞)?
f(x) = {cx^2 + 2x, x < 2 ,
2x + 4, x ≥ 2}
Solve the initial value problem dy/dx = −(2x cos(x^2))y +
6(x^2)e^(− sin(x^2)) , y(0) = −5
Solve the initial value problem dy/dt = (6t^5/(1 + t^6))y + 7(1
+ t^6)^2 , y(1) = 8.
Find the general solution of dy/dt = (2/t)*y + 3t^2* cos3t
The value of f depends on two independent variables x and y as
defined below:
f(x,y)=x2+y2−x+3cos(x)sin(y)
Function f has a minimum in the neighborhood of the origin (i.e.
[0 0]). Find x and y which minimize f.
Note: You are not allowed to use MATLAB built-in
functions for optimization. Follow the logic of the derivative
test:
The minimum of f occurs where:
∂f∂x=0∂f∂y=0