In: Statistics and Probability
From a survey of construction labor, the work duration (in number of hours) per day and the average productivity (percent efficiency) were recorded as follows:
Duration and Productivity (x, y) |
No. of Observations |
6, 45 |
4 |
6, 65 |
3 |
6, 85 |
10 |
8, 45 |
5 |
8, 65 |
36 |
8, 85 |
24 |
10, 45 |
7 |
10, 65 |
23 |
10, 85 |
13 |
12, 45 |
8 |
12, 65 |
5 |
12, 85 |
2 |
Total |
140 |
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A. Determine the marginal probability distribution function (PDF) for X, the distribution of work duration and plot graphically on px (x) versus x for y = 6, 8, 10 and 12. Present px (x) in terms of relative frequencies of the observations.
B. Similarly, determine the marginal PDF for Y, representing the distribution of productivity.
C. If the work duration per day is 10 hr, what is the probability that the average productivity will be 85%?
work duration (in number of hours) per day(X) | average productivity (percent efficiency) (Y) | No. of Observations |
6 | 45 | 4 |
6 | 65 | 3 |
6 | 85 | 10 |
8 | 45 | 5 |
8 | 65 | 36 |
8 | 85 | 24 |
10 | 45 | 7 |
10 | 65 | 23 |
10 | 85 | 13 |
12 | 45 | 8 |
12 | 65 | 5 |
12 | 85 | 2 |
Total | 140 | |
A. Determine the marginal probability distribution function (PDF) for X, the distribution of work duration and plot graphically on px (x) versus x for y = 6, 8, 10 and 12. Present px (x) in terms of relative frequencies of the observations.
work duration (in number of hours) per day(X) | Frequency | Relative Frequency |
6 | 4+3+10 = 17 | 17/140 = 0.1214 |
8 | 5+36+24 = 65 | 65/140 = 0.4643 |
10 | 7+23+13 = 43 | 43/140 = 0.3071 |
12 | 8+5+2 = 15 | 15/140 = 0.1072 |
b)
Average productivity (percent efficiency) (Y) | Frequency | Relative Frequency |
45 | 4+5+7+8 = 24 | 24/140 = 0.1714 |
65 | 3+36+23+5 = 67 | 67/140 = 0.4786 |
85 | 10+24+13+2 = 49 | 49/140 = 0.35 |
C. If the work duration per day is 10 hr, what is the probability that the average productivity will be 85%?
P[ average productivity will be 85% | work duration per day is 10 hr ]= P[ average productivity will be 85% and work duration per day is 10 hr ] / P[ work duration per day is 10 hr ]
P[ average productivity will be 85% and work duration per day is 10 hr ] = 13/140
[ work duration per day is 10 hr ] = 43/140
P[ average productivity will be 85% | work duration per day is 10 hr ]= (13/140)/(43/140)
P[ average productivity will be 85% | work duration per day is 10 hr ]= 13/43
P[ average productivity will be 85% | work duration per day is 10 hr ]=0.3023