1.50L reaction vessel was initially filled with 0.150moles of CO and 0.300moles of H2. After equilibrium...

1.50L reaction vessel was initially filled with 0.150moles of CO and 0.300moles of H2. After equilibrium is established, the vessel is found to contain 0.119moles of CO. What is the equilibrium constant for this reaction? The reaction is: CO(g) + 2H2(g) ↔ CH3OH(g)

Expert Solution

CO(g) + 2H2(g) ↔ CH3OH(g)

I 0.15 0.3 0

C -0.031 -2*0.031 0.031

E 0.119 0.238 0.031

[CO] = 0.119/1.5 = 0.079M

[H2} = 0.238/1.5 = 0.158M

[CH3OH] = 0.031/1.5 = 0.02 M

Kc = [CH3OH]/[CO][H2]²

= 0.02/0.079*(0.158)² = 10.14 >>>> answer

queen_honey_blossom answered 1 year ago

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