Question

In: Chemistry

A Diels-Alder reaction of 2,5-dimethylfuran and maleic anhydride

A Diels-Alder reaction of 2,5-dimethylfuran and maleic anhydride gives a compound A that undergoes acid- catalyzed dehydration to give 3,6-dimethylphthalic anhydride. 


(a) Deduce the structure of compound A. Draw all non-bonding electrons (as applicable) 

(b) Give a curved-arrow mechanism for the conversion of A into 3,6-dimethylphthalic anhydride. The catalyst H2SO4 is abbreviated as "H-B" below and its conjugate base is abbreviated as B Follow the directions above each drawing box. 


First step: Delete/Add bonds to form A,  Add 2 curved arrows to give next product.

Second step: Draw missing bond andcurved arrow.

A Diels-Alder reaction of 2,5-dimethylfuran and maleic anhydride gives a compound A that undergoes acid- catalyzed dehydration to give 3,6-dimethylphthalic anhydride. CH H2SO4 H2O CH H2C 3,6 maleic dimethylphthalic 2,5-dimethylfuran anhydride anhydride CH (a) Deduce the structure of compound A. Draw all non-bonding electrons (as applicable) (b) Give a curved-arrow mechanism for the conversion of A into 3,6-dimethylphthalic anhydride. The catalyst H2SO4 is abbreviated as H-B below and its conjugate base is abbreviated as B Follow the directions above each drawing box. First step: Delete/Add bonds to form A, Second step: Draw missing bond and Add 2 curved arrows to give next product curved arrow H3C O: O: H B. O: CH H3C (scroll down)


Solutions

Expert Solution

Given above is the diels-alder reaction and the further ring opening rearrangement reaction

(a) Drawn below is the structure of A (diels-alder product)

(b) mechanism for A to 3,6-dimethyl phthalic anhydride product formation

From A, first step is protonation of oxygen followed by C-C bond cleavage to generate a tertiary carbocation species. Loss of H+ gives a diene structure. Reprotonation of -OH to form H2O which leaves and gives another tertiary carbocation. Loss of another H+ gives the desired product.


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