In: Statistics and Probability
You are planning a May camping trip to Denali National Park in Alaska and want to make sure your sleeping bag is warm enough. The average low temperature in the park for May follows a normal distribution with a mean of 32°F and a standard deviation of 8°F.
1.
What is the probability that the low temperature on a given night will be between 22°F and 29°F? Include 4 decimal places in your answer.
2.
What temperature must the sleeping bag be suited such that the temperature will be too cold only 5% of the time? Include 1 decimal places in your answer.
3.
What is the probability that on a given night the low temperature will be 32°F? Include 4 decimal places in your answer.
Solution :
Given that ,
mean = = 32
standard deviation = = 8
P(22< x <29 ) = P[(22-32) /8 < (x - ) / < (29-32) /8 )]
= P( -1.25< Z <-0.375 )
= P(Z <-0.375 ) - P(Z <-1.25 )
Using z table
= 0.3538-0.1056
probability=0.2482
(b)
Using standard normal table,
P(Z < z) = 5%
= P(Z < z) = 0.05
= P(Z < -1.64) = 0.05
z = -1.64 Using standard normal z table,
Using z-score formula
x= z * +
x= -1.64*8+32
x= 18.9
(C)
P(X< 32) = P[(X- ) / < (32-32) / 8]
= P(z <0 )
Using z table
=0.5
probability=0.5