In: Math
Professor Fair believes that extra time does not improve grades on exams. He randomly divided a group of 300 students into two groups and gave them all the same test. One group had exactly 1 hour in which to finish the test, and the other group could stay as long as desired. The results are shown in the following table. Test at the 0.01 level of significance that time to complete a test and test results are independent.
Time | A | B | C | F | Row Total |
1 h | 24 | 45 | 60 | 15 | 144 |
Unlimited | 17 | 46 | 80 | 13 | 156 |
Column Total | 41 | 91 | 140 | 28 | 300 |
(i) Give the value of the level of significance.
State the null and alternate hypotheses.
H0: The distributions for a timed test and
an unlimited test are the same.
H1: The distributions for a timed test and an
unlimited test are different.H0: Time to take a
test and test score are not independent.
H1: Time to take a test and test score are
independent. H0: Time to
take a test and test score are independent.
H1: Time to take a test and test score are not
independent.H0: The distributions for a timed
test and an unlimited test are different.
H1: The distributions for a timed test and an
unlimited test are the same.
(ii) Find the sample test statistic. (Round your answer to two
decimal places.)
(iii) Find or estimate the P-value of the sample test
statistic.
P-value > 0.1000.050 < P-value < 0.100 0.025 < P-value < 0.0500.010 < P-value < 0.0250.005 < P-value < 0.010P-value < 0.005
(iv) Conclude the test.
Since the P-value < α, we reject the null hypothesis.Since the P-value is ≥ α, we do not reject the null hypothesis. Since the P-value < α, we do not reject the null hypothesis.Since the P-value ≥ α, we reject the null hypothesis.
(v) Interpret the conclusion in the context of the application.
At the 1% level of significance, there is insufficient evidence to claim that time to do a test and test results are not independent.At the 1% level of significance, there is sufficient evidence to claim that time to do a test and test results are not independent.
I) The null and alternate hypotheses are:
As we need to test whether the time to complete a test and test
results are independent, we need to perform a chi-square
independent test.
H0: Time to take a test and test score are independent.
H1: Time to take a test and test score are not independent
II) Let's calculate the test statistic from the following
formula:
Here, Oi is the observed values and Ei are the expected values for each cell
The expected value is calculated by multiplying the
corresponding row and column total and divide it by 300
(Total)
The calculations/values calculated are shown in the below
table:
Results | ||||||
A | B | C | F | Row Totals | ||
1 Hour | 24 (19.68) [0.95] | 45 (43.68) [0.04] | 60 (67.20) [0.77] | 15 (13.44) [0.18] | 144 | |
Unlimited | 17 (21.32) [0.88] | 46 (47.32) [0.04] | 80 (72.80) [0.71] | 13 (14.56) [0.17] | 156 | |
Column Totals | 41 | 91 | 140 | 28 | 300 (Grand Total) |
The expected values are given in the parenthesis () and chi-square value for the given cell is shown in []
Chi-square statistic = Sum of individual chi-square values = 3.7321
III) P-value = 0.2918 (from the table)
P-value > 0.1000
IV) As the p-value > 0.10, we will not reject the null hypothesis
Since the P-value is ≥ α, we do not reject the null hypothesis.
V) Conclusion:
At the 1% level of significance, there is insufficient evidence to claim that time to do a test and test results are not independent