Question

def check(s):
     #Conditions applied 1,5,6
     if len(s)=9 and s[0].isupper() and s[-1].isdigit():
         upper_count = sum(1 for c in s if c.isupper())
         lower_count = sum(1 for c in s if c.islower())
         number_count = sum(1 for c in s if c.isdigit())

         #Conditions 2,3,4
         if upper_count=3 and lower_count==3 and number_count==3:

             #Condition 7 { Two consecutive alphabets can’t be small }
             for i in range(1,len(s)):
                 if s[i-1].islower() and s[i].islower() :
                     return 'reject'
         else:
             return 'reject'
         #All conditions satisfies here, so accept
         return 'accept'

     else:
         return 'reject'


### TEST CASES ###
print(check('ABiG1h2f3')) #ALL correct


# BELOW ALL SHOULD BE REJECTED
print(check('AbiG1h2f3')) # bi consecutive two small letters

print(check('aBiG1h2f3')) # Starts with small letter

print(check('ABiG1h2fe')) # doesn't end with number

print(check('ABiG1h')) #Length is not 9

print(check('ABiG1h334')) # has 4 numbers. Also only 2 small letters

i need a definition of this python code?

Answer 1

Definition of each part of the provide code is explained in comments. Please go through and let me know if you have any doubts or if you need anything to change. If you are satisfied with the solution, please rate the answer. Thanks

Note: Also fixed some small bugs (i.e. found two usages of = instead of == for value comparisons, fixed it)

'''
The below method accepts a string and returns either 'accept' or 'reject' based on the
value of the string. The method returns 'accept' only if the following conditions are met
> The length of string must be 9
> There should be three upper case, 3 lower case and 3 digits characters
> There should not be any consecutive small letters like 'ac' or 'xp' etc
> First character must be a capital letter
> Last character must be a digit
The method returns 'reject' if any of these case(s) is/are violated.
'''
def check(s):
    # checking if length is 9 and first character is upper case and last
    #character is a digit
    if len(s)==9 and s[0].isupper() and s[-1].isdigit():
        #counting the number of upper, lower and numeric characters
        #(1 for c in s if c.isupper()) will return a set/list of 1's where
        #number of 1s equal to the number of upper case characters, sum() will
        #sum all these 1s, which will return the total number of upper case chars
        upper_count = sum(1 for c in s if c.isupper())
        lower_count = sum(1 for c in s if c.islower())
        number_count = sum(1 for c in s if c.isdigit())

        # checking if number of upper, lower, numeric characters are exactly 3 each
        if upper_count==3 and lower_count == 3 and number_count == 3:

            # checking if there exists a two consecutive occurrences of small letters
            for i in range(1, len(s)):
                if s[i - 1].islower() and s[i].islower():
                    #characters at i-1 and i are lower case
                    return 'reject'
        else:
            #upper or lower or numeric count not equals 3
            return 'reject'
        # All conditions satisfies here, so accept
        return 'accept'

    else:
        #length is not 9 or first character is not upper case or last character
        #is not numeric
        return 'reject'


### TEST CASES ###
print(check('ABiG1h2f3')) # ALL correct

# BELOW ALL SHOULD BE REJECTED
print(check('AbiG1h2f3')) # bi consecutive two small letters

print(check('aBiG1h2f3')) # Starts with small letter

print(check('ABiG1h2fe')) # doesn't end with number

print(check('ABiG1h')) # Length is not 9

print(check('ABiG1h334')) # has 4 numbers. Also only 2 small letters

#OUTPUT

accept

reject

reject

reject

reject

reject