Question
In: Chemistry
Determine the pH at the equivalence (stoichiometric) point in the titration of 29 mL of 0.17...
Determine the pH at the equivalence (stoichiometric) point in the titration of 29 mL of 0.17 M C6H5COOH(aq) with 0.16 M NaOH(aq). The Ka of benzoic acid is 6.5 x 10-5.
Solutions
queen_honey_blossom answered 2 years agoRelated Solutions
Determine the pH at the equivalence (stoichiometric) point in the titration of 29 mL of 0.17...
Determine the pH at the equivalence (stoichiometric) point in
the titration of 29 mL of 0.17 M C6H5COOH(aq)
with 0.16 M NaOH(aq). The Ka of benzoic acid is 6.5 x
10-5.
Determine the pH at the equivalence (stoichiometric) point in the titration of 35 mL of 0.15...
Determine the pH at the equivalence (stoichiometric) point in
the titration of 35 mL of 0.15 M acrylic acid(aq) with 0.16 M
NaOH(aq). The Ka of C2H4COOH is 5.5 x 10-5.
Determine the pH at the equivalence (stoichiometric) point in the titration of 34 mL of 0.16...
Determine the pH at the equivalence (stoichiometric) point in
the titration of 34 mL of 0.16 M C6H5OH(aq)
with 0.16 M NaOH(aq). The Ka of phenol is 1.0 x
10-10
The answer is 11.45 I'm just not sure how to get
it
Determine the pH at the equivalence (stoichiometric) point in the titration of 40 mL of 0.18...
Determine the pH at the equivalence (stoichiometric) point in
the titration of 40 mL of 0.18 M butanoic acid(aq) with 0.28 M
NaOH(aq). The Ka of
CH3CH2CH2COOH is 1.5 x
10-5.
Determine the pH at the equivalence (stoichiometric) point in the titration of 20 mL of 0.2...
Determine the pH at the equivalence (stoichiometric) point in
the titration of 20 mL of 0.2 M hydrazine(aq) with 0.14 M HCl(aq).
The Kb of hydrazine is 1.7 x 10-6. I am
trying to use the equation: ph=7+1/2(pka+logC), but I am unsure how
to find the values and plug them in correctly. The answer should be
4.66. Please show all steps clearly. Thanks!
Determine the pH at the equivalence (stoichiometric) point in the titration of 41 mL of 0.25...
Determine the pH at the equivalence (stoichiometric) point in
the titration of 41 mL of 0.25 M C6H5COOH(aq) with 0.27 M NaOH(aq).
The Ka of benzoic acid is 6.5 x 10-5.
Determine the pH at the equivalence (stoichiometric) point in the titration of 48 mL of 0.29...
Determine the pH at the equivalence (stoichiometric) point in
the titration of 48 mL of 0.29 M CH3NH2(aq)
with 0.19 M HCl(aq). The Kb of methylamineis 3.6 x
10-4.
Determine the pH at the equivalence (stoichiometric) point in the titration of 22 mL of 0.22...
Determine the pH at the equivalence (stoichiometric) point in
the titration of 22 mL of 0.22 M H3BO3(aq)
with 0.21 M NaOH(aq). The Ka of
H3BO3 is 5.8 x 10-10
Answer is 11.13
Determine the pH at the equivalence point in the titration of 47 mL of 0.26 M...
Determine the pH at the equivalence point in the titration of 47
mL of 0.26 M HF (aq) with 0.26 M NaOH (aq). The Ka of HF is 7.4 x
10^-4.
Please show detailed process. Answer should be 8.12
A) What is the pH at the equivalence point in the titration of a 15.6 mL...
A) What is the pH at the equivalence point in the titration of a
15.6 mL sample of a 0.312 M
aqueous hypochlorous acid solution with a
0.302 M aqueous barium hydroxide
solution?
pH = ___
B) When a 18.2 mL sample of a
0.426 M aqueous hypochlorous acid
solution is titrated with a 0.458 M aqueous
barium hydroxide solution, what is the pH at the
midpoint in the titration?
pH = ___
ADVERTISEMENT
ADVERTISEMENT
Latest Questions
- What are the SHDN, LNA in opamp What are the TXCO coding algorithm for binary and...
- Need to program a maze traversal program using dynamic array and stacks. The problem is faced...
- what were some of Ida B Wells significant contributions to the civil rights movement?
- In 2007, there were many people in Sri Lanka who have an opinion that the government...
- Example #2: Write the following set of four linear equations with 4 unknowns x1, x2, x3,...
- "In the digital age, our personal and collective privacy is threatened like it never has been...
- when i type those python code below, i got True, but when i type not a...
ADVERTISEMENT