One form of nuclear radiation, beta decay, occurs when a neutron changes into a proton, an...

One form of nuclear radiation, beta decay, occurs when a neutron changes into a proton, an electron and a neutral particle called a neutrino. When this change happens to a neutron within the nucleus of an atom, the proton remains behind in the nucleus while the electron and neutrino are ejected from the nucleus. The ejected electron is called a beta particle. One nucleus that exhibits beta decay is the isotope of hydrogen ³H, called tritium, whose nucleus consists of one proton (making it hydrogen) and two neutrons (giving tritium an atomic mass m = 3u). Tritium is radioactive, and it decays to helium.

Suppose an electron is ejected from a ³H atom, which has a radius of 1.000×10^-14 m. The resulting ³He atom has the same radius as the ³H atom. What is the escape velocity of the electron ejected from the process?

Note: Your answer may be larger than the speed of light which is okay in this scenario.

Expert Solution

genius_generous answered 1 year ago

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