1. A solution is prepared by adding 40.00mL of 0.125M Ba(OH)2 (aq) to 12.50mL of 0.350M...

1. A solution is prepared by adding 40.00mL of 0.125M Ba(OH)2 (aq) to 12.50mL of 0.350M HNO3(aq). Calculate the pH and pOH of the overall mixture at 298K.

Expert Solution

normality of Ba(OH)2 = acidity * molarity

= 2*0.125 = 0.25 N

nofmality of HNO3 = basicity * molarity

= 1*0.35 = 0.35 N

Ba(OH)2 NHO3

NB = 0.25N NA = 0.35N

VB = 40ml NA = 12.5ml

N = NBVB-NAVA/VA+VB

= 0.25*40-0.35*12.5/40+12.5 = 5.625/52.5 = 0.107N

N = [OH-] = 0.107N

POH = -log[OH-]

= -log0.107 = 0.9706

PH = 14-POH

= 14-0.9706 = 13.0294

queen_honey_blossom answered 2 years ago

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