Question

In: Computer Science

C/ C++ Preferably 1. Write a simple program where you create an array of single byte...

C/ C++ Preferably

1. Write a simple program where you create an array of single byte characters. Make the array 100 bytes long. In C this would be an array of char. Use pointers and casting to put INTEGER (4 byte) and CHARACTER (1 byte) data into the array and pull it out. YES, an integer can be put into and retrieved from a character array. It's all binary under the hood. In some languages this is very easy (C/C++) in others it's more difficult due to type casting restrictions (Java/Python). Make sure you can access both character and integer data at any location in the array.


In C/C++ think of the follow type of code:
int j, i, *ii;
char c, *cc;
char mem[MEM_SIZE];
ii = (int*)(mem + 10); //base address + 10
cc = mem+10;


2. Read data from a text file. Can't come up with your own test data, cut and paste the words to 'Mary had a little lamb' into a file or down load a text (.txt) version of the bible (big) from the internet.
3. Use regular expressions, strtok or any command you want including something you write yourself to break a line of text read from a file into tokens. A token is just a sequence of characters without a separator. The only separator you need is space ' ' but if you want to use more like, comma ',', tab '\t' and semicolon ';' go for it.

Solutions

Expert Solution

Answer 1

Code

#include <stdio.h>

#define MEM_SIZE 100

int main()
{
   int i, *ii;
   char *ch, c;
   char arr[MEM_SIZE] = { 0 };

   //writing value 243 in character array starting from location arr+10
   ii = (int*)(arr + 10);
   *ii = 243678782; // 3e 3e 86 0e will be stored at positions 10, 11, 12 and 13 respectively. LSB will be stored at starting position and so on

   // Retreiving value as character byte at location arr+10
   ch = (char*)(arr + 10);
   c = *ch;
   printf("Before changing value of integer starting position 10 is: %d\n", *ii);

   printf("value of c at position 10 is: %c\n", c); // c will get value as 3e which means character '>' (Ascii conversion)

   // Now change the value at location arr+10 and retrieve using integer
   *ch = '8';
   printf("Changed charater value at position 10 is: %c", *ch);
   printf("\nvalue of integer starting position 10 is: %d", *ii); // New value will become 38 3e 86 0e => 243,678,776‬. Position 10 byte is MSB.

   return 0;
}

Test Output


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