In: Math
The following relative frequency distribution was constructed
from a population of 650. Calculate the population mean, the
population variance, and the population standard
deviation.
Class | Relative Frequency |
−20 up to −10 | 0.30 |
−10 up to 0 | 0.20 |
0 up to 10 | 0.40 |
10 up to 20 | 0.10 |
Population Mean -
Population Variance -
Population Standard Deviation -
Solution:
Given that,
Class | Frequency | Relative Frequency | Mid value | fx | fx2 |
−20 up to −10 | 0.30*650 = 195 | 0.30 | -15 | -2925 | 43875 |
−10 up to 0 | 0.20 * 650 = 130 | 0.20 | -5 | -650 | 3250 |
0 up to 10 | 0.40 = 260 | 0.40 | 5 | 1300 | 6500 |
10 up to 20 | 0.10 = 65 | 0.10 | 15 | 975 | 14625 |
Total | N = 650 | fx = -1300 | fx2 = 68250 |
a ) The population mean is
= fx / N
= -1300 / 650
= - 2
The population mean is = - 2
b ) Population Variance is 2
2 = ( fd2 ) - (( fd )2 / N ) / N
= ( 68250 ( (- 1300 )2 / 650 ) / 650
= ( 68250 -2600 ) / 650
= 65650*/650
= 101
Population Variance is 2 = 101
C ) Population Standard Deviation is
= Variance
= 101
= 10.0499
Population Standard Deviation = 10.0499