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A rectangular loop of wire with sides H = 27 cm and W = 74 cm...

A rectangular loop of wire with sides H = 27 cm and W = 74 cm carries current I2 = 0.187 A. An infinite straight wire, located a distance L = 25 cm from segment ad of the loop as shown, carries current I1 = 0.781 A in the positive y-direction.

1)

What is Fad,x, the x-component of the force exerted by the infinite wire on segment ad of the loop?
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2)

What is Fbc,x, the x-component of the force exerted by the infinite wire on segment bc of the loop?.
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3)

What is Fnet,y, the y-component of the net force exerted by the infinite wire on the loop?
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5)

What is the magnitude of I3

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A rectangular loop of wire with sides H = 29 cm and W = 75 cm carries current I2= 0.202 A. An infinite straight wire, located a distance L = 26 cm from segment ad of the loop as shown, carries current I1= 0.79 A in the positive y-direction.


1)

What is Fad,x, the x-component of the force exerted by the infinite wire on segment ad of the loop?

2)

What is Fbc,x, the x-component of the force exerted by the infinite wire on segment bc of the loop?.

3)

What is Fnet,y, the y-component of the net force exerted by the infinite wire on the loop?

4)

What is the magnitude of I3?

5)

Another infinite straight wire, aligned with the y-axis is now added at a distance 2L = 52 cm from segment bc of the loop as shown. A current, I3, flows in this wire. The loop now experiences a net force of zero.


1)

Fad,x, the x-component of the force exerted by the infinite wire on segment ad of the loop?

Fad=B*I2*Lad* sin(90)...


B=uo*i1/(2*pi*L)=6.07*10^-7 T

Fad=0.355*10^-7 N


2)

Fbc,x, the x-component of the force exerted by the infinite wire on segment bc of the loop?.



Fbc,x=0..since Fnet on bc acts towards negative y-axis


3)

Fnet,y, the y-component of the net force exerted by the infinite wire on the loop?
Fnet=0.355*10^-7 N - 1.56*10^-7=-1.209 *10^-7 N
4)


the magnitude of I3


net magnetic field due to i3 at cb must be 1.56*10^-7 N to get net force on the loop is zero

B=uo*i3/(2*pi*2L)= 1.56*.26=0.4056 A



5) the direction is along the positive y-direction


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