In: Statistics and Probability
A technician compares repair costs for two types of microwave ovens (type I and type II). He believes that the repair cost for type I ovens is greater than the repair cost for type II ovens. A sample of 59 type I ovens has a mean repair cost of $71.68, with a standard deviation of $15.08. A sample of 48 type II ovens has a mean repair cost of $66.21, with a standard deviation of $10.25. Conduct a hypothesis test of the technician's claim at the 0.05 level of significance. Let μ1 be the true mean repair cost for type I ovens and μ2 be the true mean repair cost for type II ovens.
Ho : µ1 - µ2 = 0
Ha : µ1-µ2 > 0
Level of Significance , α =
0.05
Sample #1 ----> sample 1
mean of sample 1, x̅1= 71.68
standard deviation of sample 1, s1 =
15.08
size of sample 1, n1= 59
Sample #2 ----> sample 2
mean of sample 2, x̅2= 66.21
standard deviation of sample 2, s2 =
10.25
size of sample 2, n2= 48
difference in sample means = x̅1-x̅2 =
71.6800 - 66.2
= 5.47
pooled std dev , Sp= √([(n1 - 1)s1² + (n2 -
1)s2²]/(n1+n2-2)) = 13.1394
std error , SE = Sp*√(1/n1+1/n2) =
2.5540
t-statistic = ((x̅1-x̅2)-µd)/SE = (
5.4700 - 0 ) /
2.55 = 2.142
Degree of freedom, DF= n1+n2-2 =
105
p-value =
0.017263 [excel function: =T.DIST.RT(t stat,df)
]
Conclusion: p-value <α , Reject null
hypothesis
There is enough evidence to sat that the repair cost for type I
ovens is greater than the repair cost for type II ovens
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