In: Chemistry
A generic solid, X, has a molar mass of 80.4 g/mol. In a constant-pressure calorimeter, 16.0 g of X is dissolved in 337 g of water at 23.00 °C.
The temperature of the resulting solution rises to 28.70 °C. Assume the solution has the same specific heat as water, 4.184 J/(g·°C), and that there\'s negligible heat loss to the surroundings. How much heat was absorbed by the solution?
how much heat was absoped
waht is the enthrapy
total mass of mixture = 337+16 = 353 g
initial temperature = 23 c
final temperature = 28.7 c
DT = 28.7 -23 = 5.7
heat released in the process (q) = m*s*DT
= 353*4.184*5.7
= 8.42 joule
no of mole of solid = 16/80.4 = 0.2 mole
DHsol = q/n = 8.42/0.2 = 42.1 kj/mol