Question

PART 1.
A study reports the following final notation: F (2, 12) = 5.00, p > .05

a. How many samples were involved in this study?

b. How many total participants were involved in this study?

c. If MSwithin is 3, what is MSbetween?


PART 2.
Test the claim that the mean GPA for student athletes is higher than 3.1 at the .01 significance level.

Based on a sample of 50 people, the sample mean GPA was 3.15 with a standard deviation of 0.08

The test statistic is:  (to 3 decimals)

The p-value is:  (to 3 decimals)

Based on this we:

• Fail to reject the null hypothesis
• Reject the null hypothesis

Answer 1

PART 1.
A study reports the following final notation: F (2, 12) = 5.00, p > .05

a. How many samples were involved in this study?

df1 =2

df 1 = k-1

so, k-1 =2

k=3

so, total samples = 3

b. How many total participants were involved in this study?

df1 = 2

df2 =12

df total = df+ df2 = 14

and df total=N-1

so, N=14+1 = 15

so, total participants = 15

c. If MSwithin is 3, what is MSbetween?

F=MSbetween / MSwithin

so, MSbetween = F*MSwithin = 5*3=15

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part B

Ho :   µ =   3.1
Ha :   µ >   3.1
      
Level of Significance ,    α =    0.01
sample std dev ,    s =    0.08
Sample Size ,   n =    50
Sample Mean,    x̅ =   3.15
      
degree of freedom=   DF=n-1=   49
      
Standard Error , SE =   s/√n =   0.0113
      
t-test statistic=   (x̅ - µ )/SE =    4.419

p-Value   =   0.000  [excel formula for p-avlue =t.dist.rt(4.419,49) ]

p-value <α,reject Ho

Reject the null hypothesis