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Overproduction of uric acid in the body can be an indication of cell breakdown. This may...

Overproduction of uric acid in the body can be an indication of cell breakdown. This may be an advance indication of illness such as gout, leukemia, or lymphoma.† Over a period of months, an adult male patient has taken eight blood tests for uric acid. The mean concentration was x = 5.35 mg/dl. The distribution of uric acid in healthy adult males can be assumed to be normal, with σ = 1.83 mg/dl.

(a) Find a 95% confidence interval for the population mean concentration of uric acid in this patient's blood. What is the margin of error? (Round your answers to two decimal places.)

lower limit    
upper limit    
margin of error    


(b) What conditions are necessary for your calculations? (Select all that apply.)

n is largeσ is unknownuniform distribution of uric acidnormal distribution of uric acidσ is known



(c) Interpret your results in the context of this problem.

The probability that this interval contains the true average uric acid level for this patient is 0.05.There is not enough information to make an interpretation.    The probability that this interval contains the true average uric acid level for this patient is 0.95.There is a 95% chance that the confidence interval is one of the intervals containing the population average uric acid level for this patient.There is a 5% chance that the confidence interval is one of the intervals containing the population average uric acid level for this patient.


(d) Find the sample size necessary for a 95% confidence level with maximal margin of error E = 1.00 for the mean concentration of uric acid in this patient's blood. (Round your answer up to the nearest whole number.)
blood tests

Solutions

Expert Solution

Solution:

Given:

Sample size = n = 8

Sample mean =

Population standard deviation =  

Part a) Find a 95% confidence interval for the population mean concentration of uric acid

where

We need to find zc value for c=95% confidence level.

Find Area = ( 1 + c ) / 2 = ( 1 + 0.95) /2 = 1.95 / 2 = 0.9750

Look in z table for Area = 0.9750 or its closest area and find z value.

Area = 0.9750 corresponds to 1.9 and 0.06 , thus z critical value = 1.96

That is : Zc = 1.96

Thus

Thus

Lower Limit =

Lower Limit = 4.08

and

Upper Limit =

Upper Limit = 6.62

margin of error:

E = 1.2681

E = 1.27

Part b) What conditions are necessary for your calculations?

normal distribution of uric acid

σ is known

Part c) Interpret your results in the context of this problem.

There is a 95% chance that the confidence interval is one of the intervals containing the population average uric acid level for this patient.

Part d) Find the sample size

E = 1.00

c =confidence level = 95%


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