In: Chemistry
Consider the equation: 2A 1 B S 5C. If 10.0 g of A reacts with 5.00 g of B, how is the limiting reactant determined? Choose the best answer and explain.
Choosethereactantwiththesmallestcoefficientinthebal- anced chemical equation. So in this case, the limiting reac- tant is B.
Choosethereactantwiththesmallestmassgiven.Sointhis case, the limiting reactant is B.
The mass of each reactant must be converted to moles and then compared to the ratios in the balanced chemical equa- tion. So in this case, the limiting reactant cannot be deter- mined without the molar masses of A and B.
The mass of each reactant must be converted to moles first. The reactant with the fewest moles present is the limiting reactant. So in this case, the limiting reactant cannot be determined without the molar masses of A and B.
The mass of each reactant must be divided by their coeffi- cients in the balanced chemical equation, and the smallest number present is the limiting reactant. So in this case, there is no limiting reactant because A and B are used up perfectly.
2A + 1B --> 5C
m = 10 g of A react wth m = 5 g of B
we must first relate to MOLES, so we must divide by mlar masses, ignore all but
The mass of each reactant must be converted to moles and then compared to the ratios in the balanced chemical equation. So in this case, the limiting reactant cannot be determined without the molar masses of A and B.
The mass of each reactant must be converted to moles first. The reactant with the fewest moles present is the limiting reactant. So in this case, the limiting reactant cannot be determined without the molar masses of A and B.
Now.. since we do not have mlar masses, we can't determine the limiting reactant
still,
The mass of each reactant must be converted to moles and then compared to the ratios in the balanced chemical equation. So in this case, the limiting reactant cannot be determined without the molar masses of A and B. TRUE
The mass of each reactant must be converted to moles first. The reactant with the fewest moles present is the limiting reactant. So in this case, the limiting reactant cannot be determined without the molar masses of A and B.
This underlined part is false, since we must relate to ratio, if 2 mol of A ract with 1 mol of B, the, of course B is always less moles of A... but we must relate via 2:1