1.Use Newton's method to find all solutions of the equation
correct to six decimal places. (Enter your answers as a
comma-separated list.)
ln(x) = 1/(x-3)
2. Use Newton's method to find all solutions of the equation
correct to eight decimal places. Start by drawing a graph to find
initial approximations. (Enter your answers as a comma-separated
list.)
6e−x2
sin(x) = x2 −
x + 1
Use Newton's method to approximate the indicated root of the
equation correct to six decimal places.
The root of x4 − 2x3 + 4x2 − 8
= 0 in the interval [1, 2]
x = ?
Use Newton's method to find all solutions of the equation
correct to eight decimal places. Start by drawing a graph to find
initial approximations. (Enter your answers as a comma-separated
list.)
6e−x2 sin(x) = x2 − x + 1
Use Newton's method to find all solutions of the equation
correct to eight decimal places. Start by drawing a graph to find
initial approximations. (Enter your answers as a comma-separated
list.)
−2x7 − 4x4 + 8x3 + 6 = 0
Use Newton's method to find all solutions of the equation
correct to six decimal places. (Enter your answers as a
comma-separated list.)
sqrt(x + 1) = x^2 − x
What does x equal?
Use Newton's method to find all solutions of the equation
correct to eight decimal places. Start by drawing a graph to find
initial approximations. (Enter your answers as a comma-separated
list.)
4e-x2 sin(x) = x2 − x + 1
Use Newton's method to find all real roots of the equation
correct to six decimal places. (Enter your answers as a
comma-separated list.)
8/x = 1 + x^3
Using the three-step method, compute the dirty price (to 3
decimal places) of a $100 face-value bond maturing on 15-Feb-29,
paying a 5%pa semi-annual coupons with a yield to maturity of 3%pa
for settlement on 05-May-20. Set out the intermediate calculations
for each of the three steps.
(Note there are 102 days between 05-May-20 and 15-Aug-2020.
There are 182 days between 15-Feb-2020 and 15-Aug-2020)
Use Newton's method to estimate the solutions of the equation 5
x squared plus x minus 1=0. Start with x 0 equals negative 1x0=−1
for the left solution and x 0 equals 1x0=1 for the right solution.
Find x 2x2 in each case.