Question

In: Statistics and Probability

Many students graduate from college deeply in debt from student loans, credit cards, and so on....

Many students graduate from college deeply in debt from student loans, credit cards, and so on. Curious about the impact of debt on decisions about the future, a WCU sociologist took a random sample of 401 single students at WCU, classified them by a binary view of gender, and asked, “Would you consider marrying someone who was $25,000 or more in debt?” The results of this survey are shown in the following table. Test at a 1% significance level if men and women responded differently from one another. In other words, are gender and response related?

WOMEN, YES = 125

WOMEN, NO = 59

WOMEN, UNCERTAIN = 21

MEN, YES = 101

MEN, NO = 79

MEN, UNCERTAIN = 16

If This Problem Calls for:

Use Test Statistic

Use Degrees of Freedom

Pooled Variance Test

3.765

Calculate your own

Separate Variance Test

3.415

df > 75

Paired Samples Test

5.888

Calculate your own

Chi-squared Test

Calculate your own

Calculate your own

Determine which type of test is required for each question and clearly state the type of test that is called for. Then, perform all steps of the test. Show the critical value approach and the p-value approach. Explain your conclusions at the end of each test.

Solutions

Expert Solution

Answer:

The Chi-square test of independence is used.

Chi-square statistic = 5.9239

Degree of freedom = 2

Explanation:

Since we are comparing two categorical variables such that gender and the marriage decision, the Chi-square test of independence is used to test the following hypothesis,

Hypothesis:

Null hypothesis: The two variables are independent

Alternative hypothesis: The two variables are dependent

Critical value

The critical value for the chi-square statistic is obtained from the chi-square critical value table for the degree of freedom = (r-1)(c-1) = (3-1)(2-1)=2 for significance level = 0.01, the critical value is,

Test statistic

The observed values are,

. Women Men Total
Yes 125 101 226
No 59 79 138
Uncertain 21 16 37
Total 205 196 401

The expected values are obtained using the formula,

. Women Men Total
Yes 226*205/401=115.5362 226*196/401=110.4638 226
No 138*205/401=70.5486 138*196/401=67.4514 138
Uncertain 37*205/401=18.9152 37*196/401=18.0848 37
Total 205 196 401

The Chi-Square value is obtained using the formula

Observed, Oi Expected, Ei (Oi-Ei)^2/Ei
125 115.5362 0.7752
59 70.5486 1.8905
21 18.9152 0.2298
101 110.4638 0.8108
79 67.4514 1.9773
16 18.0848 0.2403
. Sum 5.9239

P-value:

The p-value is obtained from the chi-square distribution table for chi-square = 5.9239 and degree of freedom = 2

P-value = 0.0517

Decision

Critical value approach

Since the chi-square value is less than the critical value, the null hypothesis is not rejected at a 1% significance level.

P-value approach

Since the P-value is greater than 0.01 at a 1% significance level, the null hypothesis is not rejected.

Conclusion:

There is not sufficient evidence to conclude that the variables gender and marriage decision are dependent.


Related Solutions

Many students accumulate debt by the time they graduate from college. Shown in the following table...
Many students accumulate debt by the time they graduate from college. Shown in the following table is the percentage of graduates with debt and the average amount of debt for these graduates at four universities and four liberal arts colleges. University % with Debt Amount($) College % with Debt Amount($) 1 72 32,970 1 83 28,754 2 68 32,110 2 94 29,000 3 58 11,228 3 56 10,201 4 64 11,853 4 49 11,015 a. If you randomly choose a...
Assume you graduate from college with ​$32,000 in student loans. If your interest rate is fixed...
Assume you graduate from college with ​$32,000 in student loans. If your interest rate is fixed at 4.60​% APR with monthly compounding and you repay the loans over a 10​-year ​period, what will be your monthly​ payment?
Student loans: The Institute for College Access and Success reported that 69% of college students in...
Student loans: The Institute for College Access and Success reported that 69% of college students in a recent year graduated with student loan debt. A random sample of 85 graduates is drawn. Use Cumulative Normal Distribution Table as needed. Round your answers to at least four decimal places if necessary. a. Find the probability that less than 56% of the people in the sample were in debt. b. Find the probability that between 60% and 75% of the people in...
For a certain year a study reports that the percentage of college students using credit cards...
For a certain year a study reports that the percentage of college students using credit cards was 87%. A college dean of student services claims that this is too high for her university, so she randomly selects 50 students and finds that 40 of them use credit cards. At  = 0.10 is she correct? State:__________________________________ CV: use table E, F, G, CV=___________________ TV: z, t, or 2  (circle one), TV=________________ Decide:________________________________ Summary: (remember to circle the correct description...
In a recent study, approximately 42.5% of college students had student loans. A researcher was interested...
In a recent study, approximately 42.5% of college students had student loans. A researcher was interested in determining if the proportion of students that took out student loans differed by the field in which they were studying in. The following data below was collected on 865 college students in seven different fields of study. Test at α = 0.05 to determine if there are significant differences in the proportions of students that take out student loans for each of the...
****Using excel** A graduate student believed that, on the average, college students spend more time on...
****Using excel** A graduate student believed that, on the average, college students spend more time on the Internet compared to the rest of the population. She conducted a study to determine if her hypothesis was correct. The student randomly surveyed 25 students and found that the average amount of time spent on the Internet was 12.75 hours per week with a SD = 3 hours. The last census found that, on the average, people spent 11 hour per week on...
Student Debt – Vermont: The average student loan debt of a U.S. college student at the...
Student Debt – Vermont: The average student loan debt of a U.S. college student at the end of 4 years of college is estimated to be about $21,800. You take a random sample of 141 college students in the state of Vermont and find the mean debt is $23,000 with a standard deviation of $2,800. You want to construct a 99% confidence interval for the mean debt for all Vermont college students. (a) What is the point estimate for the...
Student Debt – Vermont: The average student loan debt of a U.S. college student at the...
Student Debt – Vermont: The average student loan debt of a U.S. college student at the end of 4 years of college is estimated to be about $22,500. You take a random sample of 146 college students in the state of Vermont and find the mean debt is $23,500 with a standard deviation of $2,600. We want to construct a 90% confidence interval for the mean debt for all Vermont college students. (a) What is the point estimate for the...
Explain how managing your student loans (or personal loans and debt if you don’t have student...
Explain how managing your student loans (or personal loans and debt if you don’t have student loans) can contribute to personal financial success and growth.
Eight male and eight female college students who have credit cards were surveyed and asked their...
Eight male and eight female college students who have credit cards were surveyed and asked their total credit card debt. The responses are given below in dollars: Males 1000 2100 900 1200 1300 500 1400 700 Females 1300 500 2000 1800 1300 1000 2600 1400 1. Is this an observational study or a designed experiment? Explain your answer. 2. Is it reasonable to use Welch’s t-test? Explain your answer. 3. Is there a difference in the mean credit card debt...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT