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In: Physics

Projectile Motion - (Time) Above Ground - General Launch Angle At a height h = unknown...

Projectile Motion - (Time) Above Ground - General Launch Angle

At a height h = unknown above the ground a rocket is fired at an initial speed v0 = 142.0 m/s at an angle θ = 42° above the horizontal. After a time = 25.2 s the rocket hits the ground. Ignore air resistance.

The magnitude of the gravitational acceleration is 9.8 m/s2.

Choose the RIGHT as positive x-direction. Choose UPWARD as psotitive y-direction

Keep 2 decimal places in all answers

Find v0x, the x component of the initial velocity (in m/s)

Find v0y, the y component of the initial velocity (in m/s)

(a) What maximum height (in meters) above the intial location does the rocket reach?

(b) How long (in seconds) does it take the rocket to reach the maximum heght?

(c) What is the range R (the horizontal distance) (in meters) traveled by the rocket before hitting the ground?

What is the rocket's initial height h (in meters) above the ground? Report h as positive.

(d) What is the vertical component of the velocity (in m/s) just before the rocket hits the ground? Pay attention to the direction (the sign).

(e) What is the magnitude of the velocity (including both the horizontal and vertical components) (in m/s) of the rocket just before it hits the ground?

(f) What is the direction of the velocity of the rocket just before it hits the ground?

Report the direction by an angle COUNTERCLOCKWISE from the +x axis.

Expert Solution

genius_generous answered 1 year ago

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