Question

This is just a very basic program/problem in Java I'm looking for some second opinions on.

1. Ask the user for a year input (positive integer - should be between 1500 and 2019, inclusive).

2. If the year input is not between 1500 and 2019, do not check for leap year, rather print that this year cannot be checked.

3. Take a year input from the user (should be between 1500 and 2019)

4. If the input year is a leap year, print that year is a leap year; otherwise, print that the year is not a leap year.

Answer 1

Dear Student ,

As per the requirement submitted above , kindly find the below solution.

Here a new java program with name "LeapYear.java" is created, which contains following code.

LeapYear.java :

import java.util.*;//import package
//Java class
public class LeapYear {
   // entry point , main() method
   public static void main(String[] args) {
       // creating object of Scanner class
       Scanner sc = new Scanner(System.in);
       // asking user to enter year
       System.out.print("Enter year between 1500 and 2019 : ");
       int year = sc.nextInt();// reading year
       // checking year
       if (year > 1500 && year < 2019) {
           // checking leap year
           if (((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0)) {
               // print message when year is leap year
               System.out.println(year + " is leap year.");
           } else {
               // print message when year is not leap year
               System.out.println(year + " is not leap year.");
           }
       } else {
           // print message if invalid year is entered
System.out.println("Year cannot be checked.Enter year between 1500 and 2019");
       }

   }

}

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Output : Compile and Run LeapYear.java to get the screen as shown below

Screen 1 :LeapYear.java, Screen when year is not in the range

Screen 2 :LeapYear.java, Screen showing when year is leap

Screen 3 :LeapYear.java, Screen showing when year is not leap

NOTE : PLEASE FEEL FREE TO PROVIDE FEEDBACK ABOUT THE SOLUTION.