Question

In: Math

A study regarding the relationship between age and the amount of pressure sales personnel feel in...

A study regarding the relationship between age and the amount of pressure sales personnel feel in relation to their jobs revealed the following sample information. At the 0.02 significance level, is there a relationship between job pressure and age?

Degree of Job Pressure
Age (years) Low Medium High
Less than 25 92 85 56
25 up to 40 86 63 40
40 up to 60 73 46 21
60 and older 47 18 29

State the decision rule. Use 0.02 significance level. (Round your answer to 3 decimal places.)

H0: Age and pressure are not related.

H1: Age and pressure are related.

Compute the value of chi-square. (Round your answer to 3 decimal places.)

What is your decision regarding H0?

Solutions

Expert Solution

(a)

ndf = (r - 1) X (c - 1)

= (4 - 1) X (3 - 1)

= 6

= 0.02

From Table, critical value of = 15.033

Decision Rule:
Reject null hypothesis if > 15.033

(b)

Observed Frequencies:

Low Medium High Total
Less than 25 92 85 56 233
25 up to 40 86 63 40 189
40 up to 60 73 46 21 140
60 and older 47 18 29 94
Total 298 212 146 656

Expected Frequencies are calculated as follows:

Low Medium High Total
Less than 25 105.8445 75.2988 51.8567 233
25 up to 40 85.8567 61.0793 42.0640 189
40 up to 60 63.5976 45.2439 31.1585 140
60 and older 42.7012 30.3780 20.9207 94
Total 298 212 146 656

Test Statistic is got as follows:

Observed (O) Expected (E) (O - E)2/E
92 105.8445 1.811
85 75.2988 1.250
56 51.8567 0.331
86 85.8567 0.000
63 61.0793 0.060
40 42.0640 0.101
73 63.5976 1.390
46 45.2439 0.013
21 31.1585 3.312
47 42.7012 0.433
18 30.3780 5.044
29 20.9207 3.120
Total = = 16.865

So,

The value of chi-square = 16.865

(c)

Since calculated value of = 16.865 is greater than critical value of = 15.033, the difference is significant. Reject null hypothesis.

So,

Decision regarding H0 :

Reject null hypothesis.


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