In: Math
1) For 31 randomly selected Rolling Stones concerts, the mean gross earnings is 2.61 million dollars. Assuming a population standard deviation gross earnings of 0.5 million dollars, obtain a 99% confidence interval (assume C-Level=0.99) for the mean gross earnings of all Rolling Stones concerts (in millions). Confidence interval: ___,___
2) correct interpretation for part 1 answers?
a. 99% chance that the mean gross earnings of all rolling stones concerts lies in the interval
b. 99% confident that the mean gross earning for this sample of 31 rolling stones concerts lies in the interval
c. 99% confident that the mean gross earning of all rolling stones concerts lies in the interval
d. none of the above
We have given that,
Sample mean =2.61 million dollars.
Population standard deviation=0.5 million dollars.
Sample size=31
Level of significance =1-0.99=0.01
Z critical value (by using Z table)=2.58
Confidence interval formula is
=(2.38,2.84)
Lower confidence limit =2.38 million dollars.
Upper confidence limit =2.84 million dollars.
c. 99% confident that the mean gross earning of all rolling stones concerts lies in the interval