In: Math
a bakery has bought 140 lbs of muffin dough. They want to make muffins and waffles in half dozen packs out of it. A pack of muffins requires one pound of dough & a pack of waffles requires half a pound of dough. It takes bakers 2 minutes to make a half dozen of muffins & 5 minutes to make a half dozen of waffles. The bakery make $1.50 profit on each pack of muffins and $2.00 profit on each pack of waffles. What is the max possible profit the bakery can make from the muffin dough it purchased if the bakers need to complete the baking in 10 hours or less (600 minutes)?
a)$210 b)$240 c)$310 d) $320 e)none
This is a Linear Programming problem
If there are x1 packs of waffles and x2
packs of muffins,we have to
subject to
Using graphical method , we get
To draw constraint 0.5
+
≤ 140→(1)
Treat it as 0.5
+
=140
When
= 0 then
= ?
⇒0.5(0) +
= 140
⇒
= 140
When x2 = 0 then
= ?
⇒0.5
+ (0)=140
⇒0.5
= 140
⇒
= 140 / 0.5 = 280
0 | 280 | |
| 140 | 0 |
Treat it as 5
+ 2
= 600
When
= 0 then
= ?
⇒5(0) + 2=600
⇒2
= 600
⇒
= 600 / 2 = 300
When
= 0 then
=?
⇒5
+ 2(0) = 600
⇒5
= 600
⇒
= 600 / 5 = 120
0 | 120 | |
| 300 | 0 |
The value of the objective function at each of these extreme points is as follows:
The value of the objective function at each of these extreme points is as follows:
Extreme Point Coordinates (,) |
Objective function value z = 1.5 + 2 |
O(0,0) | 1.5(0)+2(0)=0 |
A(120,0) | 1.5(120)+2(0)=180 |
B(80,100) | 1.5(80)+2(100)=320 |
C(0,140) | 1.5(0)+2(140)=280 |
The maximum value of the objective function z=320 occurs at the
extreme point (80,100).
Hence, the optimal solution to the given LP problem is :
= 80 ,
= 100 and max z=320
Answer : d) $320