Question

In: Chemistry

Calculate the pH at the equivalence point for the following titration: 0.100 M NaOH versus 1.60...

Calculate the pH at the equivalence point for the following titration: 0.100 M NaOH versus 1.60 g formic acid (HCO2H Ka = 1.8 x 10-4)

Solutions

Expert Solution

At the equivalence point we have a solution of sodium formate. As both concentrations of titrated acid and titrant are identical, and monoprotic formic acid reacts 1:1 with sodium hydroxide, we have to add identical volume of base to the given volume of acid. That in turn means that final volume is twice that of initial volume of acid sample, so after dilution concentration of formate must be half that of acid - that is 0.05 M.

We have titrated weak acid, so to calculate pH we have to calculate concentration of OH- from formate hydrolysis first. Formate is a weak base with


Related Solutions

Calculate the pH at the equivalence point for the titration of 0.100 M methylamine (CH3NH2) with...
Calculate the pH at the equivalence point for the titration of 0.100 M methylamine (CH3NH2) with 0.100 M HCl. The Kb of methylamine is 5.0
Calculate the pH at the equivalence point for the following titration: 0.10 M HCOOH versus 0.10...
Calculate the pH at the equivalence point for the following titration: 0.10 M HCOOH versus 0.10 M NaOH. (Formic Acid Ka=1.7 x 10-4)
Calculate the pH at the equivalence point in the titration of 20.00 mL of a 0.100...
Calculate the pH at the equivalence point in the titration of 20.00 mL of a 0.100 M solution of CH3NH2 (Kb for CH3NH2 = 4.4 × 10-4) with a 0.200 M HCl solution. (The reaction products are CH3NH3+ and Cl-)
What is the pH at the equivalence point for the titration of 25.00 mL 0.100 M...
What is the pH at the equivalence point for the titration of 25.00 mL 0.100 M CH3CH2CH2CO2- with 0.1848 M HCl? Species (K values) CH3CH2CH2CO2H (Ka = 1.14E-5) CH3CH2CH2CO2- (Kb = 2.63x10-10
What is the pH at the equivalence point of the titration of 50.0 mL of 0.100...
What is the pH at the equivalence point of the titration of 50.0 mL of 0.100 M HN4+ with 50.0 ml of 0.100 M NaOH? (For NH3 Kb = 1.8 x 10−5)
What is the pH at the equivalence point of the titration of 50.0 mL of 0.100...
What is the pH at the equivalence point of the titration of 50.0 mL of 0.100 M HN4+ with 50.0 ml of 0.100 M NaOH? (For NH3 Kb = 1.8 x 10−5)
Calculate the pH at the equivalence point for the titration of 1.288 M HA (a weak...
Calculate the pH at the equivalence point for the titration of 1.288 M HA (a weak acid with pKa = 2.16) with 1.288 M NaOH.
Calculate the pH at the equivalence point for the titration of 0.180 M methylamine (CH3NH2) with...
Calculate the pH at the equivalence point for the titration of 0.180 M methylamine (CH3NH2) with 0.180 M HCl. The Kb of methylamine is 5.0× 10–4.
Calculate the pH at the equivalence point in the titration of 30.0 mL of 0.135 M...
Calculate the pH at the equivalence point in the titration of 30.0 mL of 0.135 M methylamine (Kb = 4.4 × 10−4) with 0.270 M HCl.
Calculate the pH at the equivalence point for the titration of 0.230 M methylamine (CH3NH2) with...
Calculate the pH at the equivalence point for the titration of 0.230 M methylamine (CH3NH2) with 0.230 M HCl. The Kb of methylamine is 5.0× 10–4. What is the pKa of the indicator? What is the color of this indicator in a solution with pH = 6?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT