Question

Must implement a simple program that asks the user for a width and a height, storing them as double values. Afterwards, you compute area and perimeter as if the shape were a rectangle. Output the results. Then, you compute the area and perimeter as if the shape were a right triangle and you have been given the base and height.

Area and Perimeter Calculator Enter width: 3

Enter height: 5

If your shape is a rectangle, its area is 15.0 Its perimeter is 16.0

If your shape is a triangle, its area is 7.5

If it is a right triangle, its perimeter is 8.0 + square root of 34.0

Needs to be in Java

Answer 1

Explanation:

Here is the code which has the Scanner object and takes the width and height from the user.

Then it prints the area and perimeter of rectangle and triangle.

Code:

import java.util.Scanner;

public class Main
{
   public static void main(String[] args) {
      
       Scanner sc = new Scanner(System.in);
      
       System.out.println("Area and Perimeter Calculator");
       System.out.print("Enter width: ");
       double width = sc.nextDouble();
       System.out.print("Enter height: ");
       double height = sc.nextDouble();
      
       System.out.println("If your shape is a rectangle, its area is "+(width*height));
       System.out.println("Its Perimeter is "+(2*(width+height)));
       System.out.println("If your shape is a triangle, its area is "+((width*height)/2.0));
       System.out.println("If it is a right triangle, its perimeter is "+(width+height)+" + square root of "+(width*width + height*height));
      
      
   }
}

output:

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