In: Statistics and Probability
Question 1
A university claims that the average cost of books per student, per semester is $300. A group of students believes that the actual mean is higher than this. They take a random sample of 100 students and calculate the sample mean to be $345 with a standard deviation of $200.
a) Perform a z-test to see if the students are correct, that the true mean is greater than $300 using α = 0.05. Specify the hypotheses, test statistic, decision rule and conclusion.
b) Calculate the p-value for the test in part a). Does this agree with your answer to part a)? Explain why or why not.
c) Calculate a 90% confidence interval for µ. Does this agree with your answer to part a)? Explain why or why not.
To Test :-
H0 :-
H1 :-
Test Statistic :-
Z = 2.25
Test Criteria :-
Reject null hypothesis if
Result :- Reject null hypothesis
Conclusion :- There is sufficient evidence to support the claim that the actual mean is higher than $300.
Part b)
P value = P ( Z > 2.25 ) = 1 - P ( Z < 2.25 ) = 0.0122
Decision based on P value
Reject null hypothesis, if P value < level of significance
P value = 0.0122
0.0122 < 0.05, hence we reject null hypothesis
Part c)
Confidence Interval :-
Lower Limit =
Lower Limit = 312.1029
Upper Limit =
Upper Limit = 377.8971
90% Confidence interval is ( 312.1029 , 377.8971 )
Since does not lies in the interval ( 312.1029 , 377.8971 ) , we can conclude that we reject null hypothesis.