Question

In: Computer Science

using C , comments will be appreciated. I already posted this before and I am looking...

using C , comments will be appreciated. I already posted this before and I am looking for different answer.

please answer both part of the question.
A) Write down an function named bitwisedFloatCompare(float number1, float number2)

that tests whether a floating point number number1is less than, equal to or greater than another floating point number number2, by simply comparing their floating point representations bitwise from left to right, stopping as soon as the first differingbit is encountered. The fact that this can be done easily is the main motivation for biased exponent notation. The function should return 1 if number1 > number2, return -1 if number2 > number1 and should return 0 if the two numbers are equal. Please notethe solutionis constrainedto be implemented using bitwise comparison of the two numbers.

B) Write a function named printFloatRepresentation(float number) that will print the floating point representation of a number using the format given below. (Sign bit) exponent in binary (assumed bit).

significandFor example if the number passed an argument is 71 yourprogram should print

(0) 10000101 (1).00011100000000000000000

Similarly if the number passed to the function as argument is -71 the program should print

(1) 10000101 (1).00011100000000000000000

The main function and function skeletons forthe twofunctions are given in the attached C course. Complete the two functions mentioned in the question.

/*
* FloatingPointRepresentationFunctions.c
*/


//************************************************************************************/
//
//                                FloatCompare
//
//           Description:Accepts two float numbers and compares them bitwise based
//                   on floating point representations. This function will have
//                    to convert the given numbers into IEEE floating
//                    representation and then do bitwise comparison
//           Preconditions:two input arguments are passed
//           Postconditions:Returns 1,-1 or 0 based on the comparison
//                  1 if number1>number2
//                               -1 if number2>number1
//                                  0 if equal
//           Calls:           N/A
//           Called by:       main
//
//***********************************************************************************/

int bitwisedFloatCompare(float number1,float number2)
{
   // Write the function to compare and return the corresponding value


}

/*
* FloatingPointRepresentation.c
Please do not return this file or the main function with your homework
*/

#include <stdio.h>

int main()
{
   float number1;
        float number2;

   int comparison;

   number1=56;
        number2=12;

   comparison=bitwisedFloatCompare(number1,number2) ; // Compare two floating point numbers
   
   if (comparison==1)
           printf(“%f is greater than %f\n”,number1,number2);
        else if (comparison==-1)
                printf(“%f is greater than %f\n”,number2,number1);
        else if (comparison==0)
       printf(“Number are equal\n”);
        else
       printf(“Error\n);

  

   return 0;
}

Solutions

Expert Solution

A]

   int bitwisedFloatCompare(float number1,float number2){
  
    int arr1[65];
    int arr2[65];
  
    for(int i=0;i<65;i++)arr1[i]=0;
    for(int i=0;i<65;i++)arr2[i]=0;
  
    int a = number1;
    int b = number2;
  
    double remA = number1-a;
    double remB = number2-b;
  
  
    //THE ARRAY STORES IN THE FIRST 32 BITS THE BINARY REPRESENTATION OF THE INTEGRAL PART
    //AND THE NEXT POSITION IS BLANK REPRESENTING THE DECIMAL POINT
    // AND THE NEXT 32 BITS REPRESENT THE FRACTIONAL PART
  
    //BINARY REPRESENTATION OF NUMBER1 STORED IN ARR1
    int j = 31;
    while(a>0 && j>=0){
        arr1[j] = a%2;
        a = a/2;
        j--;
    }
    j = 33;
    int x;
    while(j<65){
        x = remA;
        arr1[j] = x;
        printf("%f\n",remA);
        if(x==1){
            remA = remA-1;
        }
        remA = 2*remA;
        j++;
    }
  
    //BINARY REPRESENTATION OF NUMBER2 STORED IN ARR2
    j = 31;
    while(a>0 && j>=0){
        arr2[j] = b%2;
        b = b/2;
        j--;
    }
    j = 33;
    while(j<65){
        x = remB;
        arr2[j] = x;
        if(x==1){
            remB = remB-1;
        }
        remB = 2*remB;
        j++;
    }
  
    for(int i=0;i<65;i++){
        if(i==32)
        else {
            if(arr1[i]==arr2[i]){
                continue;
            }else{
                if(arr2[i]==1 && arr1[i]==0){
                    return -1;
                }else{
                    return 1;
                }
            }
        }
    }
  
    return 0;
  
}

B]

void printBinary(int n, int i)
{

    // Prints the binary representation
    // of a number n up to i-bits.
    int k;
    for (k = i - 1; k >= 0; k--) {

        if ((n >> k) & 1)
            printf("1");
        else
            printf("0");
    }
}

typedef union {

    float f;
    struct
    {

        // Order is important.
        // Here the members of the union data structure
        // use the same memory (32 bits).
        // The ordering is taken
        // from the LSB to the MSB.
        unsigned int mantissa : 23;
        unsigned int exponent : 8;
        unsigned int sign : 1;

    } raw;
} myfloat;

// Function to convert real value
// to IEEE foating point representation
void printFloatRepresentation(myfloat var)
{

    // Prints the IEEE 754 representation
    // of a float value (32 bits)

    printf("(%d)", var.raw.sign);
    printBinary(var.raw.exponent, 8);
    printf("(1).");
    printBinary(var.raw.mantissa, 23);
    printf("\n");
}


/***** USAGE ********/

// myfloat var;

// // Get the real value
// var.f = -2.25;

// // Get the IEEE floating point representation
// printf("Float representation of %f is : \n",
//       var.f);
// printFloatRepresentation(var);

/***** END   ******/


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