In a study of the accuracy of fast food drive-through orders, Restaurant A had 266 accurate...

In a study of the accuracy of fast food drive-through orders, Restaurant A had 266 accurate orders and 63 that were not accurate.

a. Construct a 90% confidences interval estimate of the percentage of orders that are not accurate.

b. Compare the results from part (a) to this 90% confidence interval for the percentage of orders that are not accurate at Restaurant B: .0179<p<.0.249. What do you conclude?

Expert Solution

In a study of the accuracy of fast food drive-through orders, Restaurant A had 266 accurate orders and 63 that were not accurate.

That is, n = 266 and x = 63

a) Using TI-84 calculator we get, 90% confidences interval estimate of the percentage of orders that are not accurate is, ( 0.194, 0.280 )

That is, 0.194 < p < 0.280

b) 90% confidence interval for the percentage of orders that are not accurate at Restaurant B is, 0.179 < p < 0.249

The width of the confidence interval for Restaurant A is higher than the width of the confidence interval for Restaurant B.

orchestra answered 1 year ago

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