Question

In: Statistics and Probability

{Exercise 9.51 (Algorithmic)} A recent issue of the AARP Bulletin reported that the average weekly pay...

{Exercise 9.51 (Algorithmic)}

A recent issue of the AARP Bulletin reported that the average weekly pay for a woman with a high school diploma was $680 (AARP Bulletin, January–February 2010). Suppose you would like to determine if the average weekly pay for all working women is significantly greater than that for women with a high school diploma. Data providing the weekly pay for a sample of 50 working women are available in the WEBfile named WeeklyPay. These data are consistent with the findings reported in the article mentioned above. Please round answers to two decimal places if necessary. Click on the webfile logo to reference the data.

a. State the hypotheses that should be used to test whether the mean weekly pay for all women is significantly greater than the mean weekly pay for women with a high school diploma.

H0: μ - Select your answer -greater than 680greater than or equal to 680equal to 680less than or equal to 680less than 680not equal to 680
Ha: μ - Select your answer -greater than 680greater than or equal to 680equal to 680less than or equal to 680less than 680not equal to 680

b. Use the data in the WEBfile named WeeklyPay to compute the sample mean, the test statistic, and the p-value.

Sample mean
Test statistic
p-value - Select your answer -Less than .005Between .005 and .01Between .01 and .025Between .025 and .05Between .10 and .20More than .2

c. Use α = .05. What is your conclusion?
- Select your answer -The mean weekly pay for all women is higher than that for women with only a high school diploma.The mean weekly pay for all women is lesser than that for women with only a high school diploma.

d. State the rejection rule: Reject H0 if t is - Select your answer -greater than or equal togreater thanless than or equal toless thanequal tonot equal to the critical value.

Weekly Pay
582
333
759
633
629
523
320
685
599
753
553
641
290
800
696
627
679
667
542
619
950
614
548
570
678
697
750
569
679
598
596
557
657
617
1230
648
760
804
675
736
565
587
565
687
498
712
533
424
772
691

Solutions

Expert Solution

a)

Ho :   µ =   680
Ha :   µ >   680

b)

sample std dev ,    s = √(Σ(X- x̅ )²/(n-1) ) =   148.4694                  
Sample Size ,   n =    50                  
Sample Mean,    x̅ = ΣX/n =    637.9400                  
                          
degree of freedom=   DF=n-1=   49                  
                          
Standard Error , SE = s/√n =   148.4694   / √    50   =   20.9967      
t-test statistic= (x̅ - µ )/SE = (   637.940   -   680   ) /    20.997   =   -2.003

p value : More than .2

c)

p-value>α, Do not reject null hypothesis   

The mean weekly pay for all women is lesser than that for women with only a high school diploma.

d)

critical t value, t* =        1.677   [Excel formula =t.inv(α/no. of tails,df) ]

reject Ho, if t > 1.677


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