Question

Design a C program to print out the unsigned char (integer) values of the 4 bytes in sequential order (i.e., the first byte is printed first). Using the code framework provided below, the printing is done by the function void byte_value(int *), in which only pointer variables can be declared and used.
#include <stdio.h>

​

void byte_value(int *);

​

int main() {

    int n = 1;

    byte_value(&n);

    printf("Enter an integer: ");

    if (scanf("%d", &n) == 1)

        byte_value(&n);

    return 0;        

}

​

void byte_value(int *p) {

    // fill in the body using only pointer variables

    // printout the memory address of the byte and its unsigned char (integer) value

    // one line for each pair, a total of 4 lines

    return;

}

Answer 1

The function code & a sample output of running the given program is attached below:

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Function Code:

void byte_value(int *p) {

    // fill in the body using only pointer variables

    // printout the memory address of the byte and its unsigned char (integer) value

    // one line for each pair, a total of 4 lines

    unsigned char* cp = p; //create pointer of type unsigned char and point it to same address as p

    printf("%p \t %u\n",cp,*cp);  //print memory address of first byte & its unsigned char (integer) value

    printf("%p \t %u\n",cp+1,*(cp+1)); //print memory address of second byte & its unsigned char (integer) value

    printf("%p \t %u\n",cp+2,*(cp+2)); //print memory address of third byte & its unsigned char (integer) value

    printf("%p \t %u\n",cp+3,*(cp+3)); //print memory address of fourth byte & its unsigned char (integer) value

    return;

}

Output Screenshot: