In: Finance
APR and EAR: What is meant by the ”frequency of compounding”? Illustrate the meaning of the “frequency of compounding” for a one-year investment of $100 with an APR of 10% and both annual and semiannual compounding. For a monthly rate of 1%, what is the APR and EAR? What is the relationship--positive or negative--between the APR and EAR and the frequency of compounding? Use the EAR formula and make up a specific numerical example to illustrate that (a) the EAR and APR would be equal for annual compounding; and (b) that for frequencies of compounding greater than annual, the EAR would be greater than the APR.
Frequency of compounding refers to the number of times interest is compounded in a year.
For a one year investment of $100 , with annual compounding at 10% , the final amount will be $100+ 10%*100
= $110
With semi-annual compounding
The Semi-annual accumulated amount will be $100+ 5%*100 = $105
The final amount will be $105+ 5%*105 = $110.25
Thus the final amount is greater with greater compounding.
For a monthly rate of 1%,with annual compounding, both APR and EAR are same
APR= 1%
EAR= (1+APR/m)^m-1
= (1+1%/2)^2-1
=1.0025%
APR does not change with Frequency of compounding
EAR has positive relationship with Frequency of compounding.
Example:
Suppose the annual rate is 20%
For Annual compounding
EAR= (1+APR/m)^m-1 (where m=frequency of compounding)
= (1+ 20%/1)^1-1 = 20%
So the EAR and APR are the same.
For semi-annual compounding, APR will be 20%
EAR = (1+ 20%/2)^2-1
= 21%
Thus EAR is greater than APR if the frequency of compounding is higher.