Question

In: Statistics and Probability

3. The time T required to receive a message at node B from node A is...

3. The time T required to receive a message at node B from node A is an exponentially distributed random variable with mean 1/10 (milliseconds). The time T is measured from the moment that a message left node A to the moment that it was received by node B.

a) What is the probability that T exceeds 105 milliseconds?

b) What is the probability that a message is received after 200 milliseconds given that no message was received before 95 milliseconds? That is, calculate: P(T > 200 | T 95):

Solutions

Expert Solution

We are given that T is exponentially distributed with mean 1/10 (millisecond).

and the pdf and cdf of T are given by

:

(t in milliseconds)

a)

The probability that T exceeds 105 milliseconds is given by:

b)

The probability that a message is received after 200 milliseconds given that no message was received before 95 milliseconds is given by:

For any queries, feel free to comment and ask.

If the solution was helpful to you, don't forget to upvote it by clicking on the 'thumbs up' button.


Related Solutions

Given: #include <iostream> using std::cout; template <typename T> struct Node { T data; Node *link;   ...
Given: #include <iostream> using std::cout; template <typename T> struct Node { T data; Node *link;       Node(T data=0, Node *p = nullptr) { //Note, this constructor combines both default and parameterized constructors. You may modify the contructor to your needs this->data = data;        link = p; } }; template <typename T> class linked_list { Node<T> *head,*current; public: //default constructor linked_list() { head = nullptr;//the head pointer current = nullptr;//acts as the tail of the list } //destructor...
Find T(t), N(t), and B(t) for r(t) = t^2 i + (2/3)t^3 j + t k...
Find T(t), N(t), and B(t) for r(t) = t^2 i + (2/3)t^3 j + t k at the point P ( 1, (2/3) , 1)
Draw a (single) binary tree T, such that  Each internal node of T stores a...
Draw a (single) binary tree T, such that  Each internal node of T stores a single character  A preorder traversal of T yields ALGORITHMS  An inorder traversal of T yields GOLATIHRMS
Imagine you receive a phone call/text message from anactual friend or relative who asks you,...
Imagine you receive a phone call/text message from an actual friend or relative who asks you, “HOW IS YOUR ONLINE SCHOOL GOING?” Write a two-paragraph email to your instructor (Ms. Ivy) identifying how you will respond to the specific audience:In the first paragraph, identify the friend or relative you have in mind and explain what you think that person really wants to know in asking the question.In the second paragraph, explain how you will respond. What will you tell your...
Problem 3 Look back on the data from Problem 2 regarding the time required to perform...
Problem 3 Look back on the data from Problem 2 regarding the time required to perform a repetitive task (in seconds) on an assembly line for Farnsworth (the seasoned employee) and Higgenbottom (the newby). The times are shown in chronological order. a. Find a 95% confidence interval for the standard deviation of times for Farnsworth. Do the same for Higgenbottom. What do these confidence intervals indicate? b. Given that these times are listed chronologically, how useful are the confidence intervals...
Consider the linear transformation T : P1 → R^3 given by T(ax + b) = [a+b...
Consider the linear transformation T : P1 → R^3 given by T(ax + b) = [a+b a−b 2a] a) find the null space of T and a basis for it (b) Is T one-to-one? Explain (c) Determine if w = [−1 4 −6] is in the range of T (d) Find a basis for the range of T and its dimension (e) Is T onto? Explain
(+5) Level of a node in a binary tree is distance from root to that node....
(+5) Level of a node in a binary tree is distance from root to that node. For example, level of root is 0 and levels of left and right children of the root are 1. Level      Max number of nodes 1 2 4 8 16 32 64 ..      … n       ?? The maximum number of nodes on level n of a binary tree is : A          2^(n-1)                         B          2^n C          2^(n+1)                       D            2^[(n+1)//2] In the above answers, the operator...
The time T (in minutes) required to perform a certain job is uniformly distributed over the...
The time T (in minutes) required to perform a certain job is uniformly distributed over the interval [15; 60], which means that T is equally likely to take on any value in [15; 60] while it is impossible to take on any value outside that interval. 1 MATH 32 Worksheet 05: Chapter 5 Fall 2018 (a) Write down the probability mass function of T. (b) Find the probability that the job requires more than 30 minutes. (c) Given that the...
A bulldozer’s velocity (in m/s) at a time t is given by v(t)=t^2-t+3. (a)Estimate the displacement...
A bulldozer’s velocity (in m/s) at a time t is given by v(t)=t^2-t+3. (a)Estimate the displacement of the bulldozer on the time interval using 0≤t≤5 Midpoint Riemann Sum with 10 subintervals. Specify the value of,n ,Δx, and the chosen sample points. (b)Find the exact displacement of the object on the time interval 0≤t≤5 using the limit definition of the definite integral. Thank you,
m = 3sin(5*pi*t)-sin(40*pi*t)+5cos(10*pi*t) a)What is the bandwidth of the message? b)What should be the minimum cut-off...
m = 3sin(5*pi*t)-sin(40*pi*t)+5cos(10*pi*t) a)What is the bandwidth of the message? b)What should be the minimum cut-off frequency of the LPF (BWmin)? Why? What will you observe, when you choose value of BW smaller than BWmin? c)What should be the maximum cut-off frequency of the LPF (BWmax)? Why? What will you observe, when you choose value of BW higher than BWmax? d)What is the ideal sampling rate? Why? e)What is the ideal cut-off frequency of the LPF(Low Pass Filter)? Why?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT