In: Statistics and Probability
Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Enter a number. Round your answer to four decimal places.)
μ = 22; σ = 3.4
P(x ≥ 30) =
Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Enter a number. Round your answer to four decimal places.)
μ = 4; σ = 2
P(3 ≤ x ≤ 6) =
1)
Solution :
Given that ,
mean =
= 22
standard deviation =
= 3.4
P(x
30) = 1 - P(x
30)
= 1 - P((x -
) /
(30 - 22) / 3.4)
= 1 - P(z
2.35)
= 1 - 0.9906 Using standard normal table.
= 0.0094
Probability = 0.0094
2)
Solution :
Given that ,
mean =
= 4
standard deviation =
= 2
P( 3
x
6) = P(( (3 - 4 )/ 2)
(x -
) /
(6 - 4) / 2) )
P( 3
x
6) = P(-0.5
z
1)
P( 3
x
6) = P(z
1) - P(z
-0.5)
P( 3
x
6) = 0.8413 - 0.3085 Using standard normal table.
Probability = 0.5328