In: Statistics and Probability
In a club with 8 male and 10 female members, how many 4-member committees can be chosen that have
(a) at least 3 women?
(b) no more than 2 men?
Number of Male members in a club = 8
Number of Female members in a club = 10
(a) Number of 4-member committees can be choosen that have
atleast 3 women;
Option 1 : 3 women and 1 man ;
Number of ways of selecting 3 women from 10 women =
Number of ways of selecting 1 man from 8 men =
Therefore Number of ways of selecting 3 women from 10 women and selecting 1 man from 8 men =120x8 = 960
Option 2 : All 4-members are Women
Number of ways of selecting 4 women from 10 women =
Adding number of ways in option 1 and option 2 = 960 + 210 = 1170
Number of 4-member committees can be choosen that have atleast 3 women = 1170
(b) Number of 4-member committees can be choosen that have
No more than 2 men; Three options to have a 4-member committee with no more than 2 men: (0 men, 4 women), ( 1 man , 3 women) , (2 men, 2 women)
Option 1 : (0 man, 4 women)
All 4-members are Women
Number of ways of selecting 4 women from 10 women =
Option 2 :
3 women and 1 man ;
Number of ways of selecting 3 women from 10 women =
Number of ways of selecting 1 man from 8 men =
Therefore Number of ways of selecting 3 women from 10 women and selecting 1 man from 8 men =120x8 = 960
Option 3 :
2 women and 2 men ;
Number of ways of selecting 2 women from 10 women =
Number of ways of selecting 2 men from 8 men =
Therefore Number of ways of selecting 2women from 10 women and selecting 2 men from 8 men =45x28 = 1260
Adding number of ways in option 1 , option 2 and option 3= 960 + 210 +1260 = 2430
Number of 4-member committees can be choosen that have no more than 2 men = 2430