A mixture initially contains A, B, and C in the following concentrations: [A] = 0.700 M...

A mixture initially contains A, B, and C in the following concentrations: [A] = 0.700 M , [B] = 0.700 M , and [C] = 0.550 M . The following reaction occurs and equilibrium is established: A+2B⇌C At equilibrium, [A] = 0.540 M and [C] = 0.710 M . Calculate the value of the equilibrium constant, Kc.

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Expert Solution

A + 2B <-------------> C

0.7 0.7 0.55 ----------------> initial

0.7 - x 0.7 - 2x 0.55 + x ------------> equilibrium

At equilibrium :

[A] = 0.7 - x = 0.540

x = 0.160

[B] = 0.7 - 2x = 0.7 - 2 x 0.16

[B] = 0.38 M

Kc = [C] / [A][B]^2

= 0.710 / 0.540 x 0.38^2

= 9.11

equilibrium constant, Kc = 9.11

queen_honey_blossom answered 1 year ago

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