In: Accounting
Her savings in Interest in case she decides to pay off her mortgage over 20 years rather than 25 years would be $74,210.
Calculation:
Particulars | 20 years | 25 years | Savings in Interest if loan repaid in 20 years rather than 25 years | ||
Formula | Amount | Formula | Amount | ||
Loan Amount | 100000 | 100000 |
= Interest in 25 years - Interest in
20 years = 242710 - 168500 = $74,210 |
||
Interest Rate (r) compounded semi-annually | 5% | 5% | |||
Therefore, Semi-annual rate of Interest | (5%/2) | 2.50% | (5%/2) | 2.50% | |
No. of terms |
(No. of years X 2) since semi-annual |
40 |
(No. of years X 2) since semi-annual |
50 | |
Compound Interest | [P (1 + r)^n] - P | = [100000 (1 + 2.5%)^40] - 100000 | [P (1 + r)^n] - P | = [100000 (1 + 2.5%)^50] - 100000 | |
= [100000 (1.025)^ 40] - 100000 | = [100000 (1.025)^ 50] - 100000 | ||||
= [100000 X 2.6850] -100000 | = [100000 X 3.4271] -100000 | ||||
= 268500 - 100000 | = 342710 - 100000 | ||||
= 168500 | = 242710 |
Further, the calculation of monthly installment in each case i.e. 20 years and 25 years would be as under:
Particulars | 20 years | 25 years | ||
Formula | Amount | Formula | Amount | |
Monthly Interest Rate | 5%/12 | 0.42% | 5%/12 | 0.42% |
No. of Monthly Installments | No. of Years X 12 | 240 | No. of Years X 12 | 300 |
EMI | P (r(1+r)^n / ((1+r)^n-1) | = 100000 (0.0042(1+0.0042)^240 / ((1+0.0042)^240-1)) | P (r(1+r)^n / ((1+r)^n-1) | = 100000 (0.0042(1+0.0042)^300 / ((1+0.0042)^300-1)) |
= 100000 (0.0042 X 2.7343) / (2.7343 - 1) | = 100000 (0.0042 X 3.5161) / (3.5161 - 1) | |||
= 100000 (0.01148) / 1.7343 | = 100000 (0.01476) / 2.5161 | |||
= 1148 / 1.7343 | = 1476 / 2.5161 | |||
= $661.93 | = $586.62 |