Question

(Using pseucode )

2. Compute and display the value of X divided by Y if the value of Y is not zero. If Y does have the value 0 then display a message

saying, “Unable to perform the division”

4. Write an algorithm that inputs four exam scores corresponding to scores received on 3 semester tests and a Final Exam. Your algorithm should compute and display the average of all four tests weighing the final exam twice as heavily as a regular test.

5. Modify the test averaging algorithm you wrote in problem 4 above so that it reads in a total of 14 regular test scores plus a final exam score, which counts twice as much as a regular test. Use a loop to input and sum the scores.

Answer 1

/*----------------------------------------------------------------------\
|psuedo code:                               |
|   sem := 50 (max marks of sem)                   |
|   final := 100 (max marks of final twice of semester)       |
|                                   |
|   i := 0                               |
|   while i<15:                           |
|       testscore[i] := get the value of test score       |
|       i := i + 1                       |
|                                   |
|   loop over i=0 for 15 times to add score:           |
|       total := total + testscore[i]               |
|                                   |
|   avg := total / 15                       |
|                                   |
|   return avg                           |
|----------------------------------------------------------------------*/

#include<stdio.h>

int main(){
   int i=0, j=0;
   float maxsem = 50;
   float score[15], avg, total=0;

   while(i<15){
       printf("Enter test score for test %d: ", i+1);
       scanf("%f", &score[i]);
       if(score[i]>maxsem && i<14){
           printf("Max. score for sememster test is 50.\n");
       }
       else if(score[i]>(2*maxsem) && i==14){
           printf("Max. score for final test is 100.\n");
       }
       i++;
   }

   while(j<15){
       total += score[j];
       j++;
   }

   avg = total/i;
   printf("Average score: %.2f\n", avg);

return 0;
}

/*--------------------------------------------------------------\
|psuedo code:                           |
|   x := get the value of x                   |
|   y := get the value of y                   |
|                               |
|   if y == 0 :                       |
|       display("Unable to perfomr the division")   |
|   else :                           |
|       z := x/y                   |
|       display("Result: z")               |
|                               |
|--------------------------------------------------------------*/

#include<stdio.h>

int main(){
   float x, y, z;
   printf("Enter the value of x: \n");
   scanf("%f", &x);
   printf("Enter the value of y: \n");
   scanf("%f", &y);

   if (y == 0){//checking the value of Y equals to 0 or not
       printf("Unable to perform the division.\n");//display err msg
   }
   else{
       z = x/y;//performing division
       printf("X divided by Y equals : %f\n", z);//display result
   }

return 0;
}