Two point charges q1 = 5.00nC and q2 = -8.00nC are separated by 25 cm. What...

Two point charges q1 = 5.00nC and q2 = -8.00nC are separated by 25 cm.

What is the electric potential at the point between two charges at a distance 10 cm from charge q1?

What is the potential energy of the pair of charges?

What work will be done by the system to bring the charges from the initial distance of 25 cm to a distance of 5 cm between them?

Please show detailed work and diagram

Solutions

Expert Solution

The point where we want to evaluate electric potential is at distance away from charge q1, and away from q2. The electric potential at this point is the sum of electric potential due to charges q1 and q2.

The potential energy of two charges q1 and q2 separated by a distance r is

The two charges are separated by r=25cm=0.25m

When the two charges are separated by distance r=5cm=0.05m, the potential energy is

Work done by the system is equal to the change in potential energy of the system

Note that the work done by the system is positive which is compatible with the result that potential energy of the system decreases (the system when r=5cm have lesser potential to do work than system when r=25cm).

genius_generous answered 1 year ago

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