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When t = 0, the position of a point is s= 6m, and its velocity is...

When t = 0, the position of a point is s= 6m, and its velocity is v= 2m/s. From t = 0 to t= 6s, the acceleration of the point is a = 2+ 2t² m/s² .From t = 6s until it comes to rest, its acceleration is a = -4m/s²

^{a.) What is the total time of travel?}

^{b.) What total distance does the point move?}

Solutions

Expert Solution

From time to , acceleration of point is

Integraging above equation ,

By the time the point is at

Now at time , the point starts with velocity and an acceleration , finally comes to rest in a time

Using

a) Total time of travel is

b) Total distance the point moved is

genius_generous answered 10 months ago

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