Question

In: Physics

When t = 0, the position of a point is s= 6m, and its velocity is...

When t = 0, the position of a point is s= 6m, and its velocity is v= 2m/s. From t = 0 to t= 6s, the acceleration of the point is a = 2+ 2t2 m/s2 .From t = 6s until it comes to rest, its acceleration is a = -4m/s2

a.) What is the total time of travel?

b.) What total distance does the point move?

Solutions

Expert Solution

From time to , acceleration of point is

Integraging above equation ,

By the time the point is at  

Now at time , the point starts with velocity and an acceleration , finally comes to rest in a time

Using

Using

a) Total time of travel is

b) Total distance the point moved is


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