A 120-pF capacitor and a 480-pF capacitor are both charged to 3.10 kV. They are then...

A 120-pF capacitor and a 480-pF capacitor are both charged to 3.10 kV. They are then disconnected from the voltage source and are connected together, positive plate to negative plate and negative plate to positive plate.

(a) Find the resulting potential difference across each capacitor.

V_{120 pF}	=______ kV
V_{480 pF}	=______ kV

(b) Find the energy lost when the connections are made.
µJ

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Solution of above problem is provided below...

genius_generous answered 1 year ago

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