Question

In: Statistics and Probability

Sarah claims that her “miracle bait” is a more effective lure for panfish than the old-...

Sarah claims that her “miracle bait” is a more effective lure for panfish than the old- fashioned lure that Bill uses. Sarah and Bill went on 12 fishing expeditions in the same boat last summer and kept the following day-by-day record of the number of panfish they caught:

Days 1 2 3 4 5 6 7 8 9 10 11 12
Sarah 8 27 7 9 18 15 13 18 3 12 18 12
Bill 13 20 2 9 19 12 10 23 0 11 15 10

Do these statistics support Sarah’s argument sufficiently to convince Bill to switch to her “miracle bait”, which is somewhat more expensive than the bait Bill is currently using?

Solutions

Expert Solution

H0: Null Hypothesis:

HA: Alternative Hypothesis: (Claim)

From the given data, the following statistics are calculated:

n1 = 12

1 = 13.3333

s1 = 6.4149

n2 = 12

2 = 12

s2 = 6.7823

Test statistic is given by:

Take = 0.05

ndf = n1 + n2 - 2 = 12 + 12 - 2 = 22

One Tailed - Right Side Test

From Table, critical value of t = 1.7171

Since calculated value of t = 0.4947 is less than critical value of t = 1.7171, the difference is not significant. Fail to reject null hypothesis.

Conclusion;

The data do not support Sarah's argument sufficiently to convince Bill to switch to her "miracle bait" which is somewhat more expensive than the bait Bill is currently using.


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