In: Chemistry
we need some data like decay constants, initial and present day ration of element so we use some mostly useble data.
we use R0 of 1.05, and 1.35
present day ratio of 7.257x10‐2 ,
and decay constants of 9.849 x 10‐10 and 1.551x10‐10 y‐1 for 235U and 238U.
235U decays faster than 238U due to its shorter half‐life. The ratio of the two is subsequently decreasing with time. We have the two radioactive decay equations, given by
235U = 235U0 e-λ235 t .........(i)
and
238U = 238U0 e-λ238 t ...........(ii)
Dividing the first equation by the second, we now have
R(t) = R0e -(λ235 - λ238) t .....(iii)
Where R(t) is the ratio of 235U to 238U at some time t, and R0 is the initial ratio.. This just looks like a regular radioactive decay equation (but is not identical). Thus we can take the natural log of both sides to get
ln(R / R0) = -(λ235 - λ238) t .............(iv)
now put the value of assuming data
we use R0 of 1.05, and 1.35
present day ratio of 7.257x10‐2 ,
and decay constants of 9.849 x 10‐10 and 1.551x10‐10 y‐1 for 235U and 238U.
we obtain ages of 6.00, and 6.30 Ga or
6 and 6.30 billion years (109 years)