In: Statistics and Probability
Perform the appropriate hypothesis test for the problem. State the hypotheses, identify the claim, compute the test statistic and P-value, make a decision, and write the interpretation in terms of the claim. For consistency, use a significance level of 0.05 for the problem.
Two brands of components are compared by installing one of each brand randomly in the right and left sides of several randomly selected machines and noting the total machine operation time (in minutes) until the component needs to be replaced. Can you conclude that Brand 1 has a better mean lifetime based on the data below?
Machine | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
Brand 1 | 36,925 | 45,300 | 36,240 | 32,100 | 37,210 | 48,360 | 38,200 |
Brand 2 | 34,318 | 42,280 | 35,500 | 31,950 | 38,015 | 47,800 | 33,215 |
Brand 1 | Brand 2 | Difference |
36925 | 34318 | 2607 |
45300 | 42280 | 3020 |
36240 | 35500 | 740 |
32100 | 31950 | 150 |
37210 | 38015 | -805 |
48360 | 47800 | 560 |
38200 | 33215 | 4985 |
Sample mean of the difference using excel function AVERAGE(), x̅d = 1608.1429
Sample standard deviation of the difference using excel function STDEV.S() sd = 2008.1474
Sample size, n = 7
Null and Alternative hypothesis: µd = Brand 1-Brand 2
Ho : µd = 0
H1 : µd > 0 (claim)
Test statistic:
t = (x̅d)/(sd/√n) = 2.1187
df = n-1 = 6
Critical value :
Right tailed critical value, t_c = ABS(T.INV(0.05,6) ) = 1.943
p-value :
Right tailed p-value = T.DIST.RT(2.1187,6) = 0.0392
Decision:
p-value < α, Reject the null hypothesis.
There is enough evidence to conclude that Brand 1 has a better mean lifetime at 0.05 significance level.