Question

In: Physics

A juniper-wood plank measuring 0.31 ft by 1 ft by 17 ft is totally submerged in...

A juniper-wood plank measuring 0.31 ft by 1 ft by 17 ft is totally submerged in water.

(a) What is its weight?

(b) What is the buoyant force acting on it?

(c) What is the size and the direction of the net force on it?

size

direction

Solutions

Expert Solution

PART (a):

Volume of the wooden plank is given by:

Density of the plank, D = 35 lb/ft3

Therefore, It's weight is given by:

>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>

PART (b):

We have, Density of water, Dw = 62.4 lb/ft3

Buoyant force acting on it is given by:

>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>

PART (c):

Net force = Buoyant force - weight

Direction : Upwards

(Because, Buoyant force (acting upwards) is greater than it's weight which is directed downwards.)


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