In: Chemistry
You have the following stock solutions and solid chemicals in
your lab: 0.15 M NaCl 0.50 M Tris buffer, pH 8.0 25 mg/ml Bovine
serum albumin (BSA) MgCl2 (solid, anhydrous) MW = 95.211 g/mole
(95% pure) 1.0 M Glucose
How would you make 250 ml of the following solution:
0.1M NaCl, 0.05M Tris, pH 8.0, 0.25 mg/ml BSA, 100 mM MgCl2, 140
mg% glucose.