Question

In: Statistics and Probability

2a) Calculate an average and sample standard deviation for the independent variable (time of heating) and...

2a) Calculate an average and sample standard deviation for the independent variable (time of heating) and the dependent variable (number of surviving organisms) given the data in the table below.

Time (min) ... Number of Survivors

0.1 ...    2.01x10^6

7.5 ... 2.95x10^5

15 ...    8.42x10^4

22.5 ... 2.43x10^4

30 ... 6.99x10^3

2 b) Plot the number of survivors over tie on Cartesian, semi-log and log-log axes using only the data points. Identify the plot that best presents the data. Explain why this plot is better. Add a trend line that presents the data, including an R^2 value and equation.

2 c) Using the prediction equation developed in 2b, estimate the number of survivors after heating for 50 minutes. How confident is this estimate? Why?

Solutions

Expert Solution

2A and 2B

First I shall plot the graphs in cartesian co-ordinates

Now in the semi-logarithmic scale

Now I shall use logarithm for both the time and the number of survivors

From the above three plots, we can conclude that the log of the number of survivors vs time will be the best plot.

The trend line is fitted below,

The R squared value will be calculated from the excel regression equation

the R-squared value is calculated as follows:

Regression Statistics
Multiple R 0.995004438
R Square 0.990033831
Adjusted R Square 0.986711775
Standard Error 0.109909305
Observations 5
ANOVA
df SS MS F Significance F
Regression 1 3.600078535 3.600078535 298.0183808 0.000423531
Residual 3 0.036240166 0.012080055
Total 4 3.636318701
Coefficients Standard Error t Stat P-value Lower 95% Upper 95% Lower 95.0% Upper 95.0%
Intercept 6.190504392 0.085362964 72.51979185 5.77835E-06 5.918841342 6.462167442 5.918841342 6.462167442
X Variable 1 -0.080214492 0.004646557 -17.26320888 0.000423531 -0.095001912 -0.065427072 -0.095001912 -0.065427072

From the above results, we can see that the R-squared value will be 0.99 and the adjusted R-squared value will be 0.9867.

2C. If we use the regression equation, then the estimated number of survivors will be:

2.179779795

The confidence we have chosen here is 95%. That means, we are 95% sure that the number of survivors will be the same as stated.

Reason: As we have modelled the regression equation and p-values are less than 0.05, hence we can conclude that the coefficients are significant and the coefficients can be used to predict the number of the survivor with 95% confidence. Hence the statement is validated.

Hope this answer has helped you. If you have some queries regarding this, do let me know in the comment section.

Hit like if the answer really helped you.

Thanks !!


Related Solutions

Calculate the sample variance and sample standard deviation for the following frequency distribution of heights in...
Calculate the sample variance and sample standard deviation for the following frequency distribution of heights in centimeters for a sample of 8-year-old boys. If necessary, round to one more decimal place than the largest number of decimal places given in the data. Heights in Centimeters Class Frequency 120.6 - 123.6 26 123.7 - 126.7 22 126.8--129.8 34 129.9-132.9 26 133-136 44
A simple random sample of 285 part-time workers finds that the average wage is $19.43 with a standard deviation of $2.61.
A simple random sample of 285 part-time workers finds that the average wage is $19.43 with a standard deviation of $2.61. The data follows the normal curve. (Make sure to also state your results in a sentence.)a. Identify the population, sample, parameter, and statistic.b. Find an 80% confidence interval for the average wage of part-time workers.c. As part of an effort to push for higher wages, suppose that labor unions want to know, with 99% confidence, the average wage of...
Average lead time demand in a warehouse is 24000 units. The standard deviation of lead time...
Average lead time demand in a warehouse is 24000 units. The standard deviation of lead time demand is 5500 units. The warehouse orders 60000 units whenever inventory reaches 28000 units. What is the service level? A) around 72% B) around 81% C) around 77% D) around 89% E) none of the above
If the average time to finish an IQ test is 85 minutes with standard deviation of...
If the average time to finish an IQ test is 85 minutes with standard deviation of 17 minutes and assuming the data are normally distributed, 1. what percentage of test takers finish less than 117 minutes? 2. what percentage of test takers finishes between one hour to hour and half? 3. find the time that separates the slowest 15% who finish the test? 4. find the time that separates the fastest 5% who finish the test?
A sample of university students has an average GPA of 2.78 with a standard deviation of...
A sample of university students has an average GPA of 2.78 with a standard deviation of 0.45. If GPA is normally distributed, what percentage of the students has GPAs….. More than 2.3? Less than 3.0? Between 2.00 and 2.5?
1. A sample of 96 observations showed an average of 25 and a standard deviation of...
1. A sample of 96 observations showed an average of 25 and a standard deviation of 16. Construct the 90% confidence interval for the population mean. What is the lower limit of this interval? NOTE: WRITE YOUR ANSWER USING 4 DECIMAL DIGITS. DO NOT ROUND UP OR DOWN. 2. In a recent poll, from a sample of 140 likely voters, 65 answered they approve the way the president is handling his job. Compute the upper limit of the 95% confidence...
Calculate the sample variance and sample standard deviation for the following frequency distribution of heart rates...
Calculate the sample variance and sample standard deviation for the following frequency distribution of heart rates for a sample of American adults. If necessary, round to one more decimal place than the largest number of decimal places given in the data. Heart Rates in Beats per Minute Class Frequency 61 - 66 4 67 - 72 8 73 - 78 5 79 - 84 7 85 - 90 13
Calculate the sample variance and sample standard deviation for the following frequency distribution of heart rates...
Calculate the sample variance and sample standard deviation for the following frequency distribution of heart rates for a sample of American adults. If necessary, round to one more decimal place than the largest number of decimal places given in the data. Heart Rates in Beats per Minute Class Frequency 61 - 66 10 67 - 72 6 73 - 78 14 79 - 84 5 85 - 90 14
Calculate the sample standard deviation and sample variance for the following frequency distribution of final exam...
Calculate the sample standard deviation and sample variance for the following frequency distribution of final exam scores in a statistics class. If necessary, round to one more decimal place than the largest number of decimal places given in the data. Lower Bound   Upper Bound   Frequency 56 _____________64 _________13 65 _____________73 _________9 74 _____________82 _________4 83 _____________91 _________10 92 _____________100 _________6
Calculate the sample standard deviation and sample variance for the following frequency distribution of heart rates...
Calculate the sample standard deviation and sample variance for the following frequency distribution of heart rates for a sample of American adults. If necessary, round to one more decimal place than the largest number of decimal places given in the data. Heart Rates in Beats per MinuteClass Frequency 61 - 66 12 67 - 72 3 73 - 78 9 79 - 84 11 85 - 90 13
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT